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otez555 [7]
2 years ago
15

Calculate the intrapleural pressure if atmospheric pressure is 765 millimeters of mercury, assuming that the subject is at rest

(not inhaling or exhaling).
A. 4 millimeters of mercury
B. 0 millimeters of mercury
C. 761 millimeters of mercury
D. 765 millimeters of mercury
Physics
1 answer:
dimaraw [331]2 years ago
5 0

Answer:

C. 761 millimeters of mercury

Explanation:

Because it is at rest, the intrapulmonary pressure must be equal to the atmospheric pressure. And the intrapleural pressure is usually 4 millimeters of mercury (mmHg) less than the intrapulmonary pressure. So we have the following

intrapulmonary pressure = 765 millimeters of mercury

intrapleural pressure = intrapulmonary pressure - 4 millimeters of mercury

Then:

intrapleural pressure = (765 -4) millimeters of mercury

intrapleural pressure = 761 millimeters of mercury

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Inductive charging is used to wirelessly charge electronic devices ranging from toothbrushes to cell phones. Suppose the base un
denpristay [2]

Answer:

1.2*10^{-6}s

Explanation:

The problem must be addressed through the concepts of electromotive force. By Faraday's law it is defined that

\epsilon = NA \frac{dB}{dt}

Where

\epsilon = Electromotive Force

N = Number of Loops

A = Area

B = Magnetic Field (chaging through the time)

From this equation and our values, we need to find the time, then we re-arrange the equation

dt = NA \frac{dB}{\epsilon}

t = (16)(2.75*10^{-4})\frac{1.50*10^{-3}}{5.50}

t = 1.2*10^{-6}s

Therefore the time required for the magnetic field to decrease to zero from its maximum value is 1.2*10^{-6}s

8 0
2 years ago
A toy rocket is shot straight up into the air with an initial speed of 45.0 m/s how long does it takes for the rocket to reach i
Serjik [45]
It will be
45/9.8 = t
4.6 sec
3 0
2 years ago
Read 2 more answers
What is the approximate pressure of a storage cylinder of recovered r-410a that does not contain any non-condensable impurities
Aliun [14]

Answer:

173psig

Explanation:

The storage cylinder of recovered R-410A is mixture of difluoromethane and pentafluoroethane which is used as a refrigerant in air conditioning application. The refrigeration sector has low temperatures for installation. The pressure of cylinder at 80 F will be 173 psig. The pure refrigerants have inside a container have saturation temperature which is equal to ambient temperature.

8 0
2 years ago
(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500 - μC charge and flies due west at a sp
12345 [234]

(a) 2.64\cdot 10^{-8} N north

We can treat the aircraft as a single point charge moving in a magnetic field. In this case, the magnetic force exerted on the plane is

F=qvB sin \theta

where

q=0.500 \mu C = 0.500\cdot 10^{-6} C is the charge on the plane

v = 660 m/s is the velocity

B=8.00\cdot 10^{-5} T is the magnitude of the magnetic field

\theta=90^{\circ} is the angle between the direction of motion of the jet and of the magnetic field

Substituting,

F=(0.5\cdot 10^{-6})(660)(8.0\cdot 10^{-5})=2.64\cdot 10^{-8} N

The direction can be found by using Fleming's left hand rule. We have:

- index finger: magnetic field direction (straight up)

- middle finger: velocity of the plane (due west)

- force: thumb --> north

(b) Not negligible

As we can see from part (a), the magnitude of the force is not really big, so the effects are negligible.

For instance, we can compare this force with the weight of a plane. If we take a Boeing 737, its mass is about 80,000 kg, so its weight is

W=mg=(80000)(9.8)=784,000 N

As we can see, this is several orders of magnitude bigger than the magnetic force calculated at point (a), so the effects of the magnetic force are negligible.

8 0
2 years ago
A baseball pitcher throws a ball at 90.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it
Lisa [10]

Answer:

Vertical distance=  3.3803ft

Explanation:

First with the speed of the ball and the distance traveled horizontally we can determine the flight time to reach the plate:

Velocity= (90 mi/h) × (1 mile/5280ft) = 475200ft/h

Distance= Velocity × time⇒ time= 60.5ft / (475200ft/h) = 0.00012731h

time=  0.00012731h × (3600s/h)= 0.458316s

With this time we can determine the distance traveled vertically taking into account that its initial vertical velocity is zero and its acceleration is that of gravity, 9.81m/s²:

Vertical distance= (1/2) × 9.81 (m/s²) × (0.458316s)²=1.0303m

Vertical distance= 1.0303m × (1ft/0.3048m) = 3.3803ft

This is the vertical distance traveled by the ball from the time it is thrown by the pitcher until it reaches the plate, regardless of air resistance.

3 0
2 years ago
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