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lorasvet [3.4K]
2 years ago
14

A flying mosquito hits the windshield of a moving car and gets smashed, but the car is intact. Which of the following statements

is correct? Group of answer choices The force on the mosquito by the car is much larger than the force on the car by the mosquito, therefore the mosquito gets smashed but the car is intact. The force on the mosquito by the car is much larger than the force on the car by the mosquito because the car is much heavier than the mosquito. The force on the mosquito by the car has the same magnitude as the force on the car by the mosquito. The force on the mosquito by the car is much larger than the force on the car by the mosquito because the car is moving.
Physics
1 answer:
zhannawk [14.2K]2 years ago
6 0

Answer:

Action and reaction are the same

Explanation:

Let us carefully analyze the situation in the context of Newton's third law, when the car hits the mosquito exerts a force that acts on the mosquito, ACTION and the mosquito responds to the force that is being applied with a force of equal magnitude and direction or opposite applied to the car (Reaction).

Consequently, the correct answer is: The force of the car on the mosquito is of the same magnitude as that of the mosquito on the car

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Answer:

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interating both sides, we have

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x = Aexp(-Rt/L) Substituting x = E - iR we have

E - iR = Aexp(-Rt/L) when t = 0, i(0) = 0. So

E - i(0)R = Aexp(-R×0/L)

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So,

E - i(t)R = Eexp(-Rt/L)

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i(t)R = E(1 - exp(-Rt/L))

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2 years ago
The diagram shows a heat engine. In which area of the diagram is unusable thermal energy detected?
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As we see from the formula, the gravitational potential energy is directly proportional to the mass, m: therefore, if the mass of the cylinder is increased by a factor 3, then the gravitational potential energy will also increase by a factor 3.

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In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of a
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(a) The diffraction decreases

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sin \theta = \frac{n \lambda}{a}

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n is the order of the minimum

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a is the width of the opening

As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because \theta increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.

(b) 10.8^{\circ}

The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:

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in this case we have

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2 years ago
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