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1 year ago

14

Um navio cargueiro proveniente do Oceano Atlântico passa a navegar nas águas menos densas do rio Amazonas. Em comparação com a s

ituação no mar, é correto afirmar que no rio: *

1 answer:

LUCKY_DIMON [66]1 year ago

8 0

Answer:

Mas eu acho q é o empuxo será igual e a porção imersa do navio será maior.

Explanation: SE

Professor marcos vê isso kkkkkkkkkkkkk

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Snowboarder Jump—Energy and Momentum

soldier1979 [14.2K]

Answer:

THE ANSWER TERMS ARE DEFINED BLOW:-

Explanation:

MOMENTUM- IT IS THE ABILITY TO INCREASE OR DEVELOP CONSTANT FORCE.

KINETIC ENERGY:- IT IS THE ENERGY THAT A PRTICLE POSSES WHEN IT IS ACTUALLY IN MOTION.

POTENTIAL ENERGY:- IT IS THE ENERGY THAT A PARTICLE POSSES WHEN IT ACTUALLY IS IN RESTING STATE.

IN THIS ACIVITY THE SNOWBOARDER IS IN THE MOTION STATE THEREFORE HE POSSES KINETIC ENERGY AND TO MAINTAIN THAT KINEITC ENERG FOR A PERIOD OF TIME,MOMENTUM PLAYS IT'S ROLE.

4 0

1 year ago

A car is moving on a straight road in a fixed direction at a constant speed of v = 62 km/h with respect to the road. You wish to

Angelina_Jolie [31]

Answer:

A) $V=62 i + 0 j + 0 k$

B) $X=0.93 km$

Explanation:

A) In this situation we are talking about a car moving only in the X- axis, hence the velocity of the car is:

$V=62 i + 0 j + 0 k$

Where the unit vectors $i$ , $j$ and $k$ represent the components $x$ , $y$ and $z$ in the cartesian plane.

In this sense, each unit vector is defined to have a magnitude of exactly one (1).

B) Velocity is defined as the variation of position in time, if this car is moving only along the x direction we will have:

$V=\frac{X}{t}$

Clearing the position:

$X=V.t$

$X=(62 km/h)(0.015 h)$

$X=0.93 km$

5 0

2 years ago

If the surface temperature of that person's skin is 30∘C (that's a little lower than healthy internal body temperature becaus

anastassius [24]

Answer:

$E=477.92\ W.m^{-2}$

Explanation:

Given that:

Absolute temperature of the body, $T=273+30=303\ K$

emissivity of the body, $\epsilon=1$

<u>Using Stefan Boltzmann Law of thermal radiation:</u>

$E=\epsilon. \sigma.T^4$

where:

$\sigma =5.67\times 10^{-8}\ W.m^{-2}.K^{-4}$ (Stefan Boltzmann constant)

Now putting the respective values:

$E=1\times 5.67\times 10^{-8}\times 303^4$

$E=477.92\ W.m^{-2}$

5 0

1 year ago

If a pizza delivery guy declares himself the leader over the other pizza delivery people, he probably won't have many people obe

NemiM [27]

Answer:

the last one i think...

4 0

1 year ago

A bag of potato chips contains 2.00 L of air when it is sealed at sea level at a pressure of 1.00 atm and a temperature of 20.0°

Genrish500 [490]

Answer:

The volume at mountains is 2.766 L.

Explanation:

Given that,

Volume $V_{1} = 2.00\ L$

Pressure $P_{1}= 1.00\ atm$

Pressure $P_{2}= 70.0\ kPa$

Temperature $T_{1}= 20.0°C = 293\ K$

Temperature $T_{2}= 7.00°C = 280\ K$

We need to calculate the volume at mountains

Using gas law

$\dfrac{PV}{T}=\ Constant$

For both temperature,

$\dfrac{P_{1}V_{1}}{T_{1}}=\dfrac{P_{2}V_{2}}{T_{2}}$

Put the value into the formula

$\dfrac{101.325\times2}{293}=\dfrac{70\times V_{2}}{280}$

$V_{2}=\dfrac{101.325\times2\times280}{293\times70}$

$V_{2}=2.766\ litre$

Hence, The volume at mountains is 2.766 L.

5 0

1 year ago