Answer:
Second pit is 375 m deeper compared to first pit.
Explanation:
We have equation of motion s = ut + 0.5at²
First object hits the ground after 5 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 5 s
Substituting,
s = ut + 0.5 at²
s = 0 x 5 + 0.5 x 10 x 5²
s = 125 m
Depth of pit 1 = 125 m
Second object hits the ground after 10 seconds,
Initial velocity, u = 0 m/s
Acceleration, a = 10 m/s²
Time, t = 10 s
Substituting,
s = ut + 0.5 at²
s = 0 x 10 + 0.5 x 10 x 10²
s = 500 m
Depth of pit 2 = 500 m
Difference in depths = 500 - 125 = 375 m
Second pit is 375 m deeper compared to first pit.
Answer:
As the person moves down the zip wire, her increase in kinetic energy is less than her decrease in gravitational potential energy.
Explanation:
Work is done against the air resistance, causing thermal energy to transfer to the surroundings
Answer:
61578948 m/s
Explanation:
λ
= λ

687 = 570 
= 61578948 m/s
So Slick Willy was travelling at a speed of 61578948 m/s to observe this.
Answer:
The frequency of the photon decreases upon scattering
Explanation:
Here we note that when a photon is scattered by a charged particle, it is referred to as Compton scattering.
Compton scattering results in a reduction of the energy of the photon and hence an increase in the wavelength (from λ to λ') of the photon known as Compton effect.
Therefore, since the wavelength increases, we have from
λf = λ'f' = c
f = c/λ
Where:
f and f' = The frequency of the motion of the photon before and after the scattering
c = Speed of light (constant)
We have that the frequency, f, is inversely proportional to the wavelength, λ as follows;
f = c/λ
As λ = increases, and c is constant, f decreases, therefore, the frequency of the photon decreases upon scattering.
F=ma
m=total mass = 2300kg+2500kg=4800
F=18000N
a=?
a=F/m
a=18000/4800
a=3.8m/s^2
Final answer