In a charge-free region of space, a closed container is placed in an electric field. Which of the following is a requirement for
1 answer:
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<u>Answer:</u>
Velocity of rock after 2 seconds = 6.56 m/s
<u>Explanation:</u>
We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Here height of rock in meters, h =
Comparing both the equations
We will get initial velocity = 14 m/s(already given) and
So, Acceleration, a = -3.72
Now we have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
When time is 2 seconds we need to find final velocity.
v = 14 - 3.72 * 2 = 6.56 m/s.
So, Velocity of rock after 2 seconds = 6.56 m/s