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laila [671]
2 years ago
8

In a charge-free region of space, a closed container is placed in an electric field. Which of the following is a requirement for

the total electric flux through the surface of the container to be zero? (hw 2a.6)
A. The container must be oriented in a certain way.
B. The field must be uniform.
C. The container must be symmetric.
D. The requirement does not exist -the total electric flux is zero no matter what.
Physics
1 answer:
galina1969 [7]2 years ago
8 0

Answer:

D. The requirement does not exist -the total electric flux is zero no matter what.

Explanation:

According to Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times charge inside.

If charge inside is zero , total electric flux over a closed surface is equal to

zero . It has nothing to do with whether external field is uniform or not. For any external field , lines entering surface will be equal to flux going out.

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Answer:

<u>Informed Consent- The study didn't conform this ethical standard.</u>

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<u>Confidentiality- The study conforms this ethical standard.</u>

<u>Protection from harm- The study conforms this ethical standard.</u>

Explanation:

<u>Informed consent</u> is described as a procedure whereby researchers tend to provide details about specific research they are going to conduct, the risk & benefits involved in the study, different alternatives involved in the procedure, etc.

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4 0
1 year ago
Specific agricultural uses of water are all of the following except _____. evaporation growing crops raising livestock cleaning
Tamiku [17]
Evaporation.............
5 0
2 years ago
Read 2 more answers
Suppose that sunlight is incident upon both a pair of reading glasses and a pair of sunglasses. Which pair would you expect to b
Ainat [17]

Answer: the pair of sunglasses

Explanation:

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On the other hand, normal reading glasses (in which the lens glass has not been treated to filter ultraviolet sunlight) will let UV rays pass through.

Therefore, if both glasses are exposed to sunlight, the sunglasses are expected to be warmer by absorbing that radiant energy and preventing it from reaching the eyes.

4 0
2 years ago
A cylinder of radius R and height H is floating upright in
emmainna [20.7K]

Answer:

Pressure difference between Top and Bottom of the cylinder is given as

\Delta P = \frac{gH}{2}(\rho_A + \rho_B)

Explanation:

As we know that the force due to pressure is balanced by the weight of the cylinder

So we will have

F = mg

so we have

\Delta P \pi R^2 = mg

so we have

\Delta P \pi R^2 = \pi R^2(\rho_A(\frac{H}{2}) + \rho_B(\frac{H}{2}))g

so we have

\Delta P = \frac{gH}{2}(\rho_A + \rho_B)

6 0
2 years ago
A standard 1 kilogram weight is a cylinder 51.0 mm in height and 42.0 mm in diameter. Determine the density of the material
worty [1.4K]

Answer:

14160 kg/m^3

Explanation:

First of all, we need to find the volume of the cylinder.

The volume of the cylinder is given by:

V=\pi r^2 h

where:

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h=51.0 mm=0.051 m is the height

Substituting, we find

V=\pi (0.021 m)^2 (0.051 m)=7.1 \cdot 10^{-5} m^3

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d=\frac{m}{V}

where m = 1 kg is the mass. Substituting, we find

d=\frac{1 kg}{7.1\cdot 10^{-5} m^3}=14,160 kg/m^3

3 0
2 years ago
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