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drek231 [11]
2 years ago
12

A piston-cylinder chamber contains 0.1 m3 of 10 kg R-134a in a saturated liquid-vapor mixture state at 10 °C. It is heated at co

nstant temperature until the piston expands and the final volume of R-134a is 1 m3 . What is (a) the final pressure and (b) the total energy transferred to R-134a for this process?
Physics
1 answer:
vaieri [72.5K]2 years ago
6 0

Answer:

(A) 10132.5Pa

(B)531kJ of energy

Explanation:

This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.

Given

m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³

P1 = 101325Pa. M = 102.03g/mol

P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa

(B) Energy is transfered by the r134a in the form of thw work done in in expansion

W = nRTIn(V2/V1)

n = m / M = 10000/102.03 = 98.01mols

W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)

= 531kJ.

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Explanation:

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Physics help, please? :)
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Answer:

Explanation:

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4. The force of Earth’s gravity on the Sun is weaker than the force of the Sun’s gravity on Earth. The Sun’s attraction  affects the motion of Earth more than the Earth’s attraction affects the Sun’s motion because according to  Newton’s second law, force has mass as one of its factors. The Sun has a significantly higher mass than Earth,  meaning that its force of gravity would also be significantly higher. Newton’s third law is why the Earth doesn’t get  marginally closer to the Sun, stating that every action has an equal and opposite reaction. As the Sun is pulling  Earth towards itself, Earth is pulling away from the Sun.

8 0
1 year ago
Which changes would result in a decrease in the gravitational force between two objects? Check all that apply.
Rufina [12.5K]

Answer: 1. decreasing the mass of both objects

2. decreasing the mass of one of the objects

3. increasing the distance between the objects

Explanation: Hope that helped! (:

4 0
2 years ago
A 2.0-cm length of wire centered on the origin carries a 20-A current directed in the positive y direction. Determine the magnet
Mumz [18]
<h3>Question:</h3>

A 2.0-cm length of wire centered on the origin carries a 20-A current directed in the positive y direction. Determine the magnetic field at the point x = 5.0m on the x-axis.

<h3>Answer:</h3>

1.6nT [in the negative z direction]

<h2>Explanation:</h2>

The magnetic field, B, due to a distance of finite value b, is given by;

B = (μ₀IL) / (4πb\sqrt{b^2 + L^2})                -----------(i)

Where;

I = current on the wire

L = length of the wire

μ₀ = magnetic constant = 4π × 10⁻⁷ H/m

From the question,

I = 20A

L = 2.0cm = 0.02m

b = 5.0m

Substitute the necessary values into equation (i)

B = (4π × 10⁻⁷ x 20 x 0.02) / (4π x 5.0 \sqrt{5.0^2 + 0.02^2})

B = (10⁻⁷ x 20 x 0.02) / (5.0 \sqrt{5.0^2 + 0.02^2})

B = (10⁻⁷ x 20 x 0.02) / (5.0 \sqrt{25.0004})

B = (10⁻⁷ x 20 x 0.02) / (25.0)

B = 1.6 x 10⁻⁹T

B = 1.6nT

Therefore, the magnetic field at the point x = 5.0m  on the x-axis is 1.6nT.

PS: Since the current is directed in the positive y direction, from the right hand rule, the magnetic field is directed in the negative z-direction.

5 0
2 years ago
The drawing shows an object attached to an ideal spring, which is hanging from the ceiling. The unstrained length of the spring
Andrew [12]

Image is missing so I have attached it.

Also, the options are missing and it is;

A) KE is has a maximum value at position 3. EPE has a maximum value at position 2. GPE has a maximum value at position 1.

B) KE is has a maximum value at position 1. EPE has a maximum value at position 2. GPE has a maximum value at position 3.

C) KE is has a maximum value at position 2. EPE has a maximum value at position 3. GPE has a maximum value at position 1.

D) KE is has a maximum value at position 1. EPE has a maximum value at position 3. GPE has a maximum value at position 2.

E) KE is has a maximum value at position 2. EPE has a maximum value at position 1. GPE has a maximum value at position 3.

Answer:

Option C is the correct answer which says; KE is has a maximum value at position 2. EPE has a maximum value at position 3. GPE has a maximum value at position 1.

Explanation:

If an object vibrates about its mean position, under the influence of a restoring force, such that restoring force is directly proportional to the displacement from the mean position, the motion of the object is called simple harmonic motion. During Simple harmonic motion, the sum of Kinetic and potential energy remains constant.

Now, Looking at the diagram, Kinetic Energy (KE) is maximum at position 2.

Looking at the options, only C and E agree with this.

Thus, our answer is either option C or E.

However, Option E is not going to be right because it says that GPE is at a maximum at position 3, which is not true as the maximum GPE will occur at position 1.

Thus,

Option C fulfills that and therefore will be the correct answer.

7 0
2 years ago
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