The ammeter displays a reading of 0.10 A. Calculate the potential difference across the 45 Ω resistor.
1 answer:
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Given :
Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.
A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².
To Find :
The magnitude of F.
Solution :
Torque on hoop is given by :
( Moment of Inertia of hoop is MR² )
Putting value of M, R and α in above equation, we get :
Therefore, the magnitude of force F is 25 N.
Hence, this is the required solution.
Answer:
Explanation:
We define the linear density of charge as:
Where L is the rod's length, in this case the semicircle's length L = πr
The potential created at the center by an differential element of charge is:
where k is the coulomb's constant
r is the distance from dq to center of the circle
Thus.
Potential at the center of the semicircle
The strength of the magnetic field is
Explanation:
According to Faraday's Law, the magnitude of the induced emf in the coil is equal to the rate of changeof the flux linkage through the coil:
(1)
where
N = 505 is the number of turns in the coil
is the change in magnetic flux through the coil
is the time interval
The coil is rotated from a position perpendicular to the Earth's magnetic field to a position parallel to it, so the final flux is zero, and the magnitude of the flux change is simply equal to the initial flux:
where
B is the strength of the magnetic field
A is the area of the coil
is the angle between the normal to the coil and the field
The area of the coil can be written as
where
is its radius
Substituting everything into eq.(1) and solving for B, we find:
Learn more about magnetic fields:
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