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Misha Larkins [42]

2 years ago

14

A bucket of water experiencing a gravitational force of 525 N is pulled up from a water well. The net force in the y-direction i

s 45 N; therefore, the magnitude of the force of tension is
N.

1 answer:

lukranit [14]2 years ago

8 0

Answer:

6n!!!!!!!!!!!!!!!!!!

Explanation:

nnnn

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Read 2 more answers

The engine on a fighter airplane can exert a force of 105,840 N (24,000 pounds). The take-off mass of the plane is 16,875 kg. (I

FrozenT [24]

Answer:

The acceleration you can get with that engine in your car is around 70,56 $(\frac{m}{s^{2} })$ or 7,26 $(\frac{ft}{s^{2} } )$ using 1500kg of mass or 3306 pounds

Explanation:

Using the equation of the force that is:

$F=m*a$

So, you notice that you know the force that give the engine, so changing the equation and using a mass of a car in 1500 kg or 3306 pounds

$a=\frac{F}{m} =\frac{105840 N }{1500 (kg) }$

$a=\frac{105840 (\frac{kg*m}{s^{2} } )} {1500 kg }$

<em> Note: N or Newton units are: $\frac{kg * m}{s^{2} }$ </em>

$a= 70,54 \frac{m}{s^{2} }$

Also in pounds you can compared

$a= \frac{2400 lf }{3 306 lf}$

Note: lf in force units are: $\frac{lf*ft}{s^{2} }$

$a=7,26 \frac{ft}{s^{2} }$

8 0

2 years ago

One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra

sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration ( $a_{r}$ ), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

$a_{r} = 4\pi^{2}\cdot f^{2}\cdot R$ (1)

Where:

$f$ - Frequency, measured in hertz.

$R$ - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension ( $T$ ), measured in newtons, through the string, then we derive the following model:

$\Sigma F = T = m\cdot a_{r}$ (2)

Where $m$ is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

$T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R$ (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

$\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right)$ (4)

$\frac{T_{2}}{T_{1}} = 4\cdot 2$

$\frac{T_{2}}{T_{1}} = 8$

If both the radius and frequency are doubled, then the tension is increased 8 times.

5 0

2 years ago