A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begin
1 answer:
The given question is incomplete. The complete question is as follows.
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. Choose the origin to be at the location where the bullet begins to move. Then the force (in newtons) exerted by the expanding gas on the bullet is , where x is in meters. Determine the work done by the gas on the bullet as the bullet travels the length of the barrel.
Explanation:
We will calculate the work done as follows.
W =
=
=
= 7560 + 1458 - 1364.69
= 7653.31 J
or, = 7.65 kJ (as 1 kJ = 1000 J)
Thus, we can conclude that the work done by the gas on the bullet as the bullet travels the length of the barrel is 7.65 kJ.
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Complete Question
The complete Question is shown on the first uploaded image
Answer:
a
The torque acting on the particle is
b
The magnitude of the angular momentum increases relative to the origin
Explanation:
From the equation we are told that
The position of the particle is
The mass of the particle is
The time is t
The torque acting on the particle is mathematically represented as
where is change in angular momentum which is mathematically represented as
Where X mean cross- product
is the velocity which is mathematically represented as
Substituting for
Now the cross product of is mathematically evaluated as
So the angular momentum becomes
Substituting for m
Substituting into equation for torque
The magnitude of the angular momentum can be evaluated mathematically as
From the is equation we see that the magnitude of the angular momentum is varies directly with square of the time so it would relative to the origin because at the origin t= 0s and we move out from origin t increases hence angular momentum increases also
