Image is missing so I have attached it.
Also, the options are missing and it is;
A) KE is has a maximum value at position 3. EPE has a maximum value at position 2. GPE has a maximum value at position 1.
B) KE is has a maximum value at position 1. EPE has a maximum value at position 2. GPE has a maximum value at position 3.
C) KE is has a maximum value at position 2. EPE has a maximum value at position 3. GPE has a maximum value at position 1.
D) KE is has a maximum value at position 1. EPE has a maximum value at position 3. GPE has a maximum value at position 2.
E) KE is has a maximum value at position 2. EPE has a maximum value at position 1. GPE has a maximum value at position 3.
Answer:
Option C is the correct answer which says; KE is has a maximum value at position 2. EPE has a maximum value at position 3. GPE has a maximum value at position 1.
Explanation:
If an object vibrates about its mean position, under the influence of a restoring force, such that restoring force is directly proportional to the displacement from the mean position, the motion of the object is called simple harmonic motion. During Simple harmonic motion, the sum of Kinetic and potential energy remains constant.
Now, Looking at the diagram, Kinetic Energy (KE) is maximum at position 2.
Looking at the options, only C and E agree with this.
Thus, our answer is either option C or E.
However, Option E is not going to be right because it says that GPE is at a maximum at position 3, which is not true as the maximum GPE will occur at position 1.
Thus,
Option C fulfills that and therefore will be the correct answer.
Answer:
fcosθ + Fbcosθ =Wtanθ
Explanation:
Consider the diagram shown in attachment
fx= fcosθ (fx: component of friction force in x-direction ; f: frictional force)
Fbx= Fbcosθ ( Fbx: component of braking force in x-direction ; Fb: braking force)
Wx= Wtanθ (Wx: component of weight in x-direction ; W: Weight of semi)
sum of x-direction forces = 0
fx+ Fbx=Wx
fcosθ + Fbcosθ =Wtanθ
Answer:
Hello there use something that looks like this
Explanation:
This is an accurate representation of something you are working on!
As you can see the wire and the core are represented on the left and is showing how it can be represented on your right hand and how they are similar!
#1
In order to chase the fish the distance traveled by sea lion in time t must be equal to the distance of sea lion from the fish and distance traveled by fish in the same time.
So here we can say let say sea lion chase the fish in time "t"
then here we have
here
d1 = distance covered by sea lion in time t
d2 = distance covered by fish in the same time t
L = distance between fish and sea lion initially = 60 m
So it will take 9 s to chase the fish by sea lion
# 2
velocity of truck on road = 25 m/s along North
velocity of dog inside the truck = 1.75 m/s at 35 degree East of North
we can write the relative velocity as
now plug in the velocity of truck in this
so it is given as
direction will be given as
so with respect to ground dog velocity is 26.44 m/s towards 2.2 degree East of North
Answer:
D.
Explanation:
In order to know how long after Bill released his rock should Ted throw his if they want the stones to hit the water simultanously, we need to calculate the time needed to hit the water to both rocks independent each other, and just take the difference.
For the rock dropped by Bill, as the only influence on it is gravity (accelerating it downwards with an acceleration equal to g), and v₀ =0, we can use the following kinematic equation:
where y = height = 40 ft.
As all the parameters are given in SI units, it is advisable to convert this value to m, as follows:
Now, we can solve for t, as follows:
For the rock thrown down at 10 m/s, the kinematic equation we just have used becomes:
This leaves us a quadratic equation on t, as follows:
Taking the positive root, we have:
t = -1.02 s + 1.88 s = 0.86 s
So, in order to get that both rocks hit the water at the same time, Ted will need to wait the difference between both times:
Δt = 0.86 s - 1.58s = -0.72 s