Answer:
t = 1.02 s
Explanation:
The computation of the time required is shown below:
The package speed for belt is
= 3 - 1
= 2 m/s
Moreover, the decelerative force would be acted on the block i.e u.m.g
So, the decelerative produced
= 0.2 × 9.81
= 1.962 m/s^2
And, final velocity = 0
v = u - at
here
V = 0 = final velocity
u = 2 m/s
so,
0 = 2 - 1.962 × t
t = 1.02 s
Answer:
26.67 m/s
Explanation:
From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.
p=mv where p is momentum, m is the mass of object and v is the speed of the object
Initial momentum
The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero
Final momentum
Answer:
the new diameter of the third ring = 0.607 mm
Explanation:
Consider the radius of bright ring when air is in between the lens and the plate ;
Using the expression: for the radius of the
bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;
where;
= number of fringe
λ = wavelength
R = radius
n = refractive index of water
Now ;
the radius r of the third bright ring when the air is in between lens and plate =
The new radius of the third bright fringe is
Calculating the new diameter ; we have:
d(3) = 2(r(3))
d(3) = 2(0.3035)
d = 0.607 mm
Thus, the new diameter of the third ring = 0.607 mm
As we know that range of the projectile motion is given by
here we know that range will be same for two different angles
so here we can say the two angle must be complementary angles
so the two angles must be
so it is given that one of the projection angle is 75 degree
so other angle for same range must be 90 - 75 = 15 degree
so other projection angle must be 15 degree