Packages having a mass of 6 kgkg slide down a smooth chute and land horizontally with a speed of 3 m/sm/s on the surface of a co
1 answer:
Answer:
t = 1.02 s
Explanation:
The computation of the time required is shown below:
The package speed for belt is
= 3 - 1
= 2 m/s
Moreover, the decelerative force would be acted on the block i.e u.m.g
So, the decelerative produced
= 0.2 × 9.81
= 1.962 m/s^2
And, final velocity = 0
v = u - at
here
V = 0 = final velocity
u = 2 m/s
so,
0 = 2 - 1.962 × t
t = 1.02 s
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Answer:
A. 0.432
B. -1.92
C. 1.44 units/second
D. -3.2 units/second
Explanation:
A. To calculate her x position, we just use the following equation of motion to find the distance traveled:
here s = displacement
t = time (in seconds)
a = acceleration
Solving for the distance, we get:
s = 0.432 m
Since 0.432 meters east is equals to 0.432 meter in the positive x-direction, the x position is also 0.432.
B. Since the skater has a constant v - velocity of -3.2 m/s, (south means negative y axis), the total distance traveled is:
Distance = speed * time = -3.2 * 0.6 = -1.92 m
The answer is -1.92 units in the y-axis.
C. The x velocity component is the final speed in the east direction, which is going to be:
v = 1.44 units/second (in positive x direction)
D. Her y velocity component does not change, since the velocity towards the south is a constant 3.2 m/s
Thus the answer is -3.2 units/second in the y-axis.
To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as
Here,
=frequency received by detector
=frequency of wave emitted by source
=velocity of detector
=velocity of source
v=velocity of sound wave
Replacing we have that,
Therefore the frequencty that will hear the passengers is 422Hz
<span>In the physics lab, a cube slides down a frictionless incline as shown in the figure below, check the image for the complete solution:
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