Answer:
speed = 44.9m/s
x = 35.5 m, y = 58.0m
Explanation:
A car on a circular track with constant angular velocity ω can be described by the equation of position r:

The velocity v is given by:

The acceleration a:

From the given values we get two equations:

We also know:

The magnitude of the acceleration a is:

The magnitude of position r is:

Plugging in to the equation for a(t):

and solving for ω:

Now solve for time t:

Using the calculated values to compute v(t):

The speed of the car is:

The position r:

Answer:
The average magnitude of magnetic field B= 0.0433/ d Tesla
(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)
Explanation:
Induced emf
where B= magnetic field
d= breadth of rectangular piece
V= velocity with which the rectangular piece = o.o6m/s
n= no of turns = 10
EMF = 26mV
since d (breadth of the frame) is not given, I will use it as a variable
EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)
From eq 1, we get
B= (EMF)/(n d V)
B= (26 X 0.001) / (10 d 0.06)
B= 0.0433/ d Tesla
Answer:
Output power of the circuit is 3 Watt.
Given:
loss in decibles = 3 dB
Input power = 6 Watt
To find:
Output power = ?
Formula used:
Output power = Input power × loss in ratio
Solution:
3 dB loss = 0.5 ratio
Output power is given by,
Output power = Input power × loss in ratio
Output power = 6 × 0.5
Output power = 3 Watt
Thus, output power of the circuit is 3 Watt.
Answer:
C = 3.77*10⁻¹⁰ F = 377 pF
Q = 1.13*10⁻⁵ C
Explanation:
Given
D = 8.0 cm = 0.08 m
d = 0.95 cm = 0.95*10⁻² m
k = 80.4 (dielectric constant of the milk)
V = 30000 V
C = ?
Q = ?
We can get the capacitance of the system applying the formula
C = k*ε₀*A / d
where
ε₀ = 8.854*10⁻¹² F/m
and A = π*D²/4 = π*(0.08 m)²/4
⇒ A = 0.00502655 m²
then
C = (80.4)*(8.854*10⁻¹² F/m)*(0.00502655 m²) / (0.95*10⁻² m)
⇒ C = 3.77*10⁻¹⁰ F = 377 pF
Now, we use the following equation in order to obtain the charge on each plate when they are fully charged
Q = C*V
⇒ Q = (3.77*10⁻¹⁰ F)*(30000 V)
⇒ Q = 1.13*10⁻⁵ C