Answer:
0.647 nC
Explanation:
The force experienced by a charge due to the presence of an electric field is given by

where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

Therefore, if the electric field magnitude is

Then the charge on each antenna would be

Answer:
V₂ = 1.5 m/s
Explanation:
given,
speed of the first piece = 6 m/s
speed of the third piece = 3 m/s
speed of the second fragment = ?
mass ratios = 1 : 4 : 2
fragment break fly off = 120°
α = β = γ = 120°
sin α = sin β = sin γ = 0.866
using lammi's theorem

A,B and C is momentum of the fragments

4 x V₂ = 2 x 3
V₂ = 1.5 m/s
Answer:
The amplitude is 2.3 m
The Wavelength is 8.6 m
The frequency is 0.16 Hz
The time period is 6.25 sec
The equation that governs the behavior is ![Y=(2.3)sin[(\frac{2\pi}{8.6} )x -(\frac{2\pi}{6.2} )t]](https://tex.z-dn.net/?f=Y%3D%282.3%29sin%5B%28%5Cfrac%7B2%5Cpi%7D%7B8.6%7D%20%29x%20-%28%5Cfrac%7B2%5Cpi%7D%7B6.2%7D%20%29t%5D)
Explanation:
The explanation is shown on the first uploaded image
Answer:
Part(a): The angular acceleration is
.
Part(b): The angular displacement is
.
Explanation:
Part(a):
If
be the initial angular speed, final angular speed and angular acceleration of the centrifuge respectively, then from rotational kinematic equation, we can write

where '
' is the time taken by the centrifuge to increase its angular speed.
Given,
,
and
. From equation (
), the angular acceleration is given by

Part(b):
Also the angular displacement (
) can be written as
