Answer:
The change in gravitational potential energy is 45 J.
Explanation:
Given that,
Mass = 3 kg
Distance = 1.5 m
Gravitational field strength = 10 N/kg
We need to calculate the change in gravitational potential energy
Using formula of gravitational potential energy

Put the value into the formula


Hence, The change in gravitational potential energy is 45 J.
Answer:
P = 216 Watts
Explanation:
Given that,
Resistance 1, 
Resistance 2, 
Voltage, V = 36 V
We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.
Firstly, lets find current of the 6 ohms resistor such that,
V = IR

The power dissipated by 6 ohms resistor is given by :


So, the power dissipated across 6 ohm resistor is 126 watts.
Answer:
0.076 m/s
Explanation:
Momentum is conserved:
m v = (m + M) V
(0.111 kg) (55 m/s) = (0.111 kg + 80. kg) V
V = 0.076 m/s
After catching the puck, the goalie slides at 0.076 m/s.
Answer:
0.266 m
Explanation:
Assuming the lump of patty is 3 Kg then applying the principal of conservation of linear momentum,
P= mv where p is momentum, m is mass and v is the speed of an object. In this case
where sunscripts p and b represent putty and block respectively, c is common velocity.
Substituting the given values then
3*8=v(15+3)
V=24/18=1.33 m/s
The resultant kinetic energy is transferred to spring hence we apply the law of conservation of energy
where k is spring constant and x is the compression of spring. Substituting the given values then

Answer:
35 J
Explanation:
The man is holding the box: this means that he is applying a force vertically upward, to balance the weight of the box (which pushes downward).
Therefore, we can ignore the horizontal displacement of the man, because the force applied (vertically upward) is perpendicular to that displacement (horizontal), so the work done for that is zero.
So, only the vertical motion contributes to the work. The work done by the man is equal to the gain in gravitational potential energy of the box, so:

where
is the weight of the box
is the vertical displacement
Substituting, we find
