Answer:
The force will increase in proportion to the mass of the objects
Explanation:
The acceleration due to gravity is always the same. It is expressed in meters per second squared or m/s². The figure of 9.81 m/s² is an average value that was taken after calculating the acceleration under different surfaces. In fact, the acceleration differs depending on the shape of the part of the earth in relation to the earth's magnetic field and force.
Thus, if one washer was 20 kg, the acceleration being 9.81 m/s² the weight will be:
F = ma
=
If there are there washers, the weight will be:
F = 3 * 20 * 9.81
= 588.6 N
Answer: m= 35.6 kg
Explanation:
For finding the mass of the stone we have the formula
v=
Here, Tension= m*g = m*9.81
and linear mass density=
Linear mass density=
Linear mass density= 0.0127 kg/m
Velocity=
Velocity= 2 *
Velocity= 165.8 m/s
So putting all these values in equation we get
v=
165.8=
Solving we get
m= 35.58 kg
or m= 35.6 kg
Answer:
The amount of heat required is
Explanation:
From the question we are told that
The mass of water is
The temperature of the water before drinking is
The temperature of the body is
Generally the amount of heat required to move the water from its former temperature to the body temperature is
Here is the specific heat of water with value
So
=>
Generally the no of mole of sweat present mass of water is
Here is the molar mass of sweat with value
=>
=>
Generally the heat required to vaporize the number of moles of the sweat is mathematically represented as
Here is the latent heat of vaporization with value
=>
=>
Generally the overall amount of heat energy required is
=>
=>
Answer:
a) a = g / 3
b) x (3.0) = 14.7 m
c) m (3.0) = 29.4 g
Explanation:
Given:-
- The following differential equation for (x) the distance a rain drop has fallen has the form:
- Where, v = Speed of the raindrop
- Proposed solution to given ODE:
v = a*t
Where, a = acceleration of raindrop
Find:-
(a) Using the proposed solution for v find the acceleration a.
(b) Find the distance the raindrop has fallen in t = 3.00 s.
(c) Given that k = 2.00 g/m, find the mass of the raindrop at t = 3.00 s.
Solution:-
- We know that acceleration (a) is the first derivative of velocity (v):
a = dv / dt ... Eq 1
- Similarly, we know that velocity (v) is the first derivative of displacement (x):
v = dx / dt , v = a*t ... proposed solution (Eq 2)
v .dt = dx = a*t . dt
- integrate both sides:
∫a*t . dt = ∫dt
x = 0.5*a*t^2 ... Eq 3
- Substitute Eq1 , 2 , 3 into the given ODE:
0.5*a*t^2*g = 0.5*a^2 t^2 + a^2 t^2
= 1.5 a^2 t^2
a = g / 3
- Using the acceleration of raindrop (a) and t = 3.00 second and plug into Eq 3:
x (t) = 0.5*a*t^2
x (t = 3.0) = 0.5*9.81*3^2 / 3
x (3.0) = 14.7 m
- Using the relation of mass given, and k = 2.00 g/m, determine the mass of raindrop at time t = 3.0 s:
m (t) = k*x (t)
m (3.0) = 2.00*x(3.0)
m (3.0) = 2.00*14.7
m (3.0) = 29.4 g