Answer:
None of the option is correct
A=-4µC, B=0 C, C=0 C
C will be +4.0 µC deficient after the contact
Explanation:
A and B are come in contact together, the charge will flow to establish equilibrium, and hence becoming: A=-4µC, B=-4µC, C=+4.0 µC
Similarly when C and B touch, the positive and the negative will exact the same force due to equal charge magnitude and become electrically neutral : A=-4µC, B=0 C, C=0 C.
Answer:
(A) 10132.5Pa
(B)531kJ of energy
Explanation:
This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.
Given
m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³
P1 = 101325Pa. M = 102.03g/mol
P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa
(B) Energy is transfered by the r134a in the form of thw work done in in expansion
W = nRTIn(V2/V1)
n = m / M = 10000/102.03 = 98.01mols
W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)
= 531kJ.
No, she has it backward. Waves interfere with each other and reflect off objects. When two waves overlap their amplitudes add. If they have the same sign this addition is constructive, meaning the amplitudes grow. If they have opposite signs this constitutes subtraction and the waves can partially, or completely cancel. This is known as interference. Reflection occurs when waves travel from one medium to another. If the wave impedance of the new medium is different (which it generally is) there will be a partial, or even total, reflection.
Explanation:
It is given that,
The distance between the first spot and the central minimum is, s = 0.007 cm
Length, l = 12 m
Wavelength, 
We need to find the width of the hair. Using the condition of diffraction pattern as :
, d is the width of the hair
d = 0.00102
or
So, the width of the hair is 
. Hence, this is the required solution.
Answer:
Amplitude, A = 0.049 meters
Explanation:
Given that,
A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :
.......(1)
The general equation of a wave is given by :
.......(2)
A is amplitude of wave
On comparing equation (1) and (2) we get :
A = 0.049 meters
So, the amplitude of the wave is 0.049 meters.
