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Katyanochek1 [597]
1 year ago
6

1. A particular lever is 90.0% efficient. If 50.0 J of work are done on the lever, then how much work does the lever do on its l

oad? 2.The mechanical advantage of a pulley system is 4.00. Using this pulley system, how much force do you need to exert to lift a 500.0 N box?
Physics
1 answer:
laila [671]1 year ago
8 0

Answer:

Explanation:

Using the efficiency formula;

Efficiency = Work done by the machine (output)/work done on the machine (input) ×100%

Efficiency =w/50 ×100

90 = 100w/50

Cross multiply

90×50 = 100W

4500 = 100W

W = 4500/100

W = 45Joules

Hence the lever does 45Joules of work on its load

2) Mechanical Advantage= Load/Effort

Given

MA = 4

Load = 500N

4 = 500/Effort

Effort = 500/4

Effort =125N

Hence the effort required to lift the load is 125N

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Nicki rides her bike at a constant speed for 6 km. That part of her ride takes her 1 h. She then rides her bike at a constant sp
Savatey [412]

km x h = km/h

First trial: 6 x 1 = 6km/h

Second trial: 9 x 2 = 18km/h

6 + 18 = <u>24km/h</u> (Total)

Or

6 + 9 = 15 km

2 + 1 = 3h

15 + 3 = 18

15 x 2 = 30

3 x 2 = 6

30 - 6 = <u>24km/h</u>

8 0
2 years ago
What type of roadway has the highest number of hazards per mile?
Oliga [24]
The roadway with the highest number of hazards is <span>city streets</span>
4 0
1 year ago
A biker travels at an average speed of 18 km/hr along a 0.30 km straight segment of a bike path. How much time (in hours) does t
lawyer [7]

Answer: 0.016 h

Explanation:

\text{Average speed} = \frac{\text {Total Distance}}{\text {total time taken}}

It is given that, biker has an average speed = 18 km/h

Total distance traveled = 0.30 km

Therefore, time taken by biker to travel this distance:

\Rightarrow \text{total time taken} = \frac{0.30 km}{18 km/h}=0.016 h

Thus, the biker takes 0.016 hours to travel the segment of 0.30 km at an average speed of 18 km/h.

7 0
2 years ago
How high above the earth's surface is g reduced to 8.80m/^2?
Sladkaya [172]
Gravity changes as the altitude change.<span> The gravitational force is proportional to 1/R2,  where R is the distance from the center of the Earth the radius of earth where gravity is 9.8 m/s^2 is 6400 km this will serve as the zero mark.

g1/(g2) = R2^2/(R1)^2

so we set the constant values to R1 and the unknown distance as x

(9.8)/(8.80) = (6400-x)2/(6400)^2

solving for x we will get 

x = 345.85 km above the earths surface
</span>

<span>Hope my answer would be a great help for you.    
If </span>you have more questions feel free to ask here at Brainly.

<span> </span>


6 0
2 years ago
Read 2 more answers
Car B is following Car A and has a greater speed than Car A. the two cars are moving in a straight line and in the same directio
ElenaW [278]

Answer:

Collision force will be same in both the cases.

Explanation:

A perfectly inelastic collision is said to take place  when a system loses the amount of its Kinetic Energy at its maximum. In a perfectly inelastic collision,  the colliding particles stick to each other. In such a collision, kinetic energy is lost by combining the two bodies with each other.

In situation 1:

Speed of Car A, v_{A} = 10 mph

Speed of Car B, v_{B} = 20 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Now, in the situation 2:

Speed of car A, v_{A} = 30 mph

Speed of car B, v_{B} = 40 mph

Relative speed of car A and car B, v = v_{b} - v_{a} = 10 m/s

Therefore, Car A and Car B both have the same relative speed, v = 10 m/s

7 0
1 year ago
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