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Katyanochek1 [597]
1 year ago
6

1. A particular lever is 90.0% efficient. If 50.0 J of work are done on the lever, then how much work does the lever do on its l

oad? 2.The mechanical advantage of a pulley system is 4.00. Using this pulley system, how much force do you need to exert to lift a 500.0 N box?
Physics
1 answer:
laila [671]1 year ago
8 0

Answer:

Explanation:

Using the efficiency formula;

Efficiency = Work done by the machine (output)/work done on the machine (input) ×100%

Efficiency =w/50 ×100

90 = 100w/50

Cross multiply

90×50 = 100W

4500 = 100W

W = 4500/100

W = 45Joules

Hence the lever does 45Joules of work on its load

2) Mechanical Advantage= Load/Effort

Given

MA = 4

Load = 500N

4 = 500/Effort

Effort = 500/4

Effort =125N

Hence the effort required to lift the load is 125N

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Two vectors A and B are added together to form a vector C. The relationship between the magnitudes of the vectors is given by A
il63 [147K]

Answer:

The question is incomplete, below is the complete question

"Two vectors A and B are added together to form a vector C. The relationship between the magnitudes of the vectors is given by A + B = C. Which one of the following statements concerning these vectors is true?

a. A and B must be displacements.

b. A and B must have equal lengths.

c.A and B must point in opposite direction.

d. A and B must point in the same direction.

e.A and B must be at right angles to each other."

answer:

d. A and B must point in the same direction.

Explanation:

a.false:From vector analysis, all forms of vector with the same unit can be added, and we add vector component by component. hence this defile option (a).

b. false: in addition of vectors, length is not a criteria to consider before carrying out the operation, hence vectors of different lengths can be  added

c. false: this is against the claim as vectors in opposite direction can give rise to a new vector of negative value.

d. true: this is true as vector in the same direction add up to give rise to another vector.

e.false: this is not a true assumption

4 0
2 years ago
At what height h above the ground does the projectile have a speed of 0.5v?
maw [93]

Answer:

h=\dfrac{3v^2}{8g}

Explanation:

It is given that,

Speed of the projectile is 0.5 v. Let h is the height above the ground. Using the first equation of motion to find it.

v=u+at

v=u-gt

Initial speed of the projectile is v and final speed is 0.5 v.

0.5v=v-gt

t=\dfrac{v}{2g}

g is the acceleration due to gravity

Let h is the height above the ground. Using the second equation of motion as :

h=vt-\dfrac{1}{2}gt^2

h=v\dfrac{v}{2g}-\dfrac{1}{2}g(\dfrac{v}{2g})^2

h=\dfrac{3v^2}{8g}

So, the height of the projectile above the ground is \dfrac{3v^2}{8g}. Hence, this is the required solution.

6 0
1 year ago
A rocket is sitting on the launch pad. The engines ignite, and the rocket begins to rise straight upward, picking up speed as it
grandymaker [24]

Answer:

e. Only the rocket's motion from the top of its flight path until just before landing is free-fall.

Explanation:

A free-fall  is a fall just under force of gravity. The rocket;s upward motion is result of engine push - even if it was shut down  - and rocket free of engine push effect when it reaches it's maximum height after shutting down of engine. Then rockets stops at it's maximum height for a moment and rtuens back as free fall with only force of gravitation pulling it back to ground with acceleration 'g'.

4 0
1 year ago
The main equation we are using to measure the e/m ratio is:
kow [346]

Answer:

a.

Explanation:

the electrons beams deflection radius will be halved.

6 0
1 year ago
Two red blood cells each have a mass of 9.05×10−14 kg and carry a negative charge spread uniformly over their surfaces. The repu
Nastasia [14]

Answer:

v = 302.923 m/s

Explanation:

We can answer this question using conservation of energy. Since there is no energy loss (e.g. no viscous drag) the energy when they are far apart and the energy when they barely touch must be the same.

The initial energy must be equal to the sum of their kinetic energies, since they are far apart to feel their electrical interaction.

Ei = (1/2)mv1^2 + (1/2)m*v2^2

Let us consider that they move with the same speed:

Ei = mv^2

If we consider the case when they barely touch, there won't be any kinetic energy, just pure electromagnetic energy:

Ef = k q1q2/(r1+r2) = k q1q2/(2r1)

Since Ei = Ef

v^2 = (k/m) q1q2/(2r1)

where

  k = 8.98755 x10^9 Nm^2/C^2

  m = 9.05 x10^-14 kg

  q1 = −2.10 pC

  q2 = −3.30 pC

  r1 = 3.75×10^−6 m

v^2 = 91762.4 m^2/s^2

v = 302.923 m/s

6 0
2 years ago
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