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e-lub [12.9K]
1 year ago
6

The total charge that an automobile battery can supply without being recharged is given in terms of ampere-hours. A typical 12 V

battery has a rating of 60 ampere-hours (60 A for 1 h, 30 A for 2 h, and so on). Suppose that you forget to turn off the headlights in your parked automobile. If each of the two head-lights draws 3.8 A, how long will it be before your battery is dead?
Physics
1 answer:
Lelechka [254]1 year ago
6 0

Answer:

7.894 Hours.

Explanation:

Based on information number hours that this battery will last with give load  has mathematical relation of.

t = \frac{60Ah}{load in amperes.}

with load 60A t =  1h, 30A t = 2h so on and forth.

two head lights draw total current of 2x3.8A = 7.6A.

putting this in above relation gives.

t = \frac{60Ah}{7.6A}=7.894 h.

That is how long will it be before battery is dead.

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A student attaches a block to a vertical spring so that the block-spring system will oscillate if the block-spring system is rel
vodka [1.7K]

Answer:

Time period of the motion will remain the same while the amplitude of the motion will change

Explanation:

As we know that time period of oscillation of spring block system is given as

T= 2\pi\sqrt{\frac{M}{k}}

now we know that

M = mass of the object

k = spring constant

So here we know that the time period is independent of the gravity

while the maximum displacement of the spring from its mean position will depends on the gravity as

mg = kx

x = \frac{mg}{k}

so we can say that

Time period of the motion will remain the same while the amplitude of the motion will change

4 0
2 years ago
Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. The electric field at a point P, which
krok68 [10]

Answer:

E_{max}=41666.66\ N/C

Explanation:

Given that,

The radius of sphere, r = 0.3 m

Distance from the center of the sphere to the point P, x = 0.5 m

Electric field at point P, E_P=15000\ N/C (radially outward)

The maximum electric field is at the surface of the sphere. We know that the electric field is inversely proportional to the distance. So,

\dfrac{E_{max}}{E_p}=\dfrac{0.5^2}{0.3^2}

\dfrac{E_{max}}{15000}=\dfrac{0.5^2}{0.3^2}

{E_{max}}=\dfrac{0.5^2}{0.3^2}\times 15000

E_{max}=41666.66\ N/C

So, the magnitude of the electric field due to this sphere is 41666.66 N/C. Hence, this is the required solution.

6 0
1 year ago
If the intensity level by 15 identical engines in a garage is 100 dB, what is the intensity level generated by each one of these
insens350 [35]

To develop this problem it is necessary to apply the concepts related to Sound Intensity.

By definition the intensity is given by the equation

\beta = 10Log(\frac{I}{I_0})

Where,

I = Intensity of Sound

I_0= Intensity of Reference

At this case we have that 15 engines produces 15 times the reference intensity, that is

I= 15I_0

And the total mutual intensity is 100 dB, so we should

\beta = 100-10*log(\frac{15I_0}{I_0})

\beta = 100-10*log(15)

\beta = 100-11.76

\beta = 88.23dB

Therefore each one of these engines produce D. 88dB.

5 0
1 year ago
Disturbed by speeding cars outside his workplace, Nobel laureate Arthur Holly Compton designed a speed bump (called the "Holly h
Bezzdna [24]
:<span>  </span><span>30.50 km/h = 30.50^3 m / 3600s = 8.47 m/s 

At the top of the circle the centripetal force (mv²/R) comes from the car's weight (mg) 

So, the net downward force from the car (Fn) = (weight - centripetal force) .. and by reaction this is the upward force provided by the road .. 

Fn = mg - mv²/R 
Fn = m(g - v²/R) .. .. 1800kg (9.80 - 8.47²/20.20) .. .. .. ►Fn = 11 247 N (upwards) 
(b) 
When the car's speed is such that all the weight is needed for the centripetal force .. then the net downward force (Fn), and the reaction from the road, becomes zero. 

ie .. mg = mv²/R .. .. v² = Rg .. .. 20.20m x 9.80 = 198.0(m/s)² 

►v = √198 = 14.0 m/s</span>
3 0
2 years ago
Dao makes a table to identify the variables used in the equations for centripetal acceleration. A 2 column 5 rows. The first col
Zanzabum

Answer:

Column X. Tangential Speed

Column Y. radius  

Explanation:

The equation for centripetal acceleration is

           a_{c} = v² / r

Where v is the tangential velocity of the body and the radius of curvature.

To analyze this equation you must place the tangential velocity in one column and in the other the turning radius

Let's check the answers

Column X. Tangential Speed

Column Y. radius  

This is the correct answer.

5 0
1 year ago
Read 2 more answers
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