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vovangra [49]
2 years ago
14

Person X pushes twice as hard against a stationary brick wall as person Y. Which one of the following statements is correct?

Physics
1 answer:
Mrac [35]2 years ago
6 0

Answer:

D) Both do zero work

Explanation:

The work done by a force is given by:

W=Fd cos \theta

where

F is the force applied

d is the displacement

\theta is the angle between the direction of the force and the displacement

From the formula, we notice that work is done online when the displacement is non-zero, so when the object is moving.

In this problem, the wall is stationary: this means that the displacement is zero, d = 0, so no work is done.

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A 60 kg bicyclist going 2 m/s increased his work output by 1,800 J. What was his final velocity?
Bas_tet [7]
Bicyclist initial kinetic energy is Ek=(1/2)*m*v² where m is his mass and v is his speed and that is equal to:

Ek=(1/2)*60*2²=120 J.

When we add the increased work output, we get the total kinetic energy:

Ek(total)=Ek+W= 120 J + 1800 J= 1920 J

So Ek(total)=1920 J = (1/2)*m*V² where V is the speed after the bicyclist increased his work output. So lets solve for V:

(1/2)*60*V²=1920

30*V²=1920, we divide by 30,

V²=64, and take the square root of both sides,

V=8 m/s. 

So the speed of the bicyclist after the increased work output is V=8 m/s.
3 0
2 years ago
Read 2 more answers
A gannet is a seabird that fishes by diving from a great height
antoniya [11.8K]
For constant acceleration along a given direction, we can relate acceleration, velocity and position with the following equation that doesn't involve time:
v^{2}=  v_{0}^{2}+2a(x- x_{0})
In this equation x is the final position, which we take to be 0.  Also the initial velocity Vo is zero.  Thus the equation simplifies to 
v^{2}= 2a(- x_{0})
Putting in v=32m/s, a=-9.81m/s^2 gives
32^{2}= 2(-9.81)(- x_{0})

\frac{32^{2}}{2*9.81}= x_{0}=52.19m
3 0
2 years ago
2H2S(g)⇌2H2(g)+S2(g),Kc=1.67×10−7 at 800∘C is carried out at the same temperature with the following initial concentrations: [H2
scoray [572]

Answer : The concentration of S_2 at equilibrium will be, 1.67\times 10^{-7}M

Explanation :  Given,

Equilibrium constant = 1.67\times 10^{-7}

Initial concentration of H_2S = 0.100 M

Initial concentration of H_2 = 0.100 M

Initial concentration of S_2 = 0.00 M

The balanced equilibrium reaction is,

                      2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

Initial conc.    0.1                0.1          0

At eqm.         (0.1-2x)       (0.1+2x)      x

The expression of equilibrium constant for the reaction will be:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Now put all the values in this expression, we get :

1.67\times 10^{-7}=\frac{(0.1+2x)^2\times (x)}{(0.1-2x)^2}

By solving the term 'x' by quadratic equation, we get two value of 'x'.

x=1.67\times 10^{-7}M

Concentration of S_2 at equilibrium = x=1.67\times 10^{-7}M

Therefore, the concentration of S_2 at equilibrium will be, 1.67\times 10^{-7}M

6 0
2 years ago
Read 2 more answers
How far could a rabbit run if it ran 36km/h for 5.0min?
Korolek [52]

3 kilometers, it is just 5/60 or 1/12 multiplied by 36.

4 0
2 years ago
Read 2 more answers
It takes a slug 20 minutes to travel from the grass to the trash can , a trip of 15 meters. How far could the slug travel in 60
inn [45]

Answer:

45 meters

Explanation:

20 min = 15 meters

So if 20 x 3 = 60

you have to do 3 x 15 !

- which equals to 45 <3

<u>- mark me brainlest pls . </u>

5 0
2 years ago
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