Answer:
0.5 m
Explanation:
Givens:
ym1 = 2.5 mm
ym2 = 4.5 mm
Ф_1=π / 4
Ф_2=π / 2
We have 2 ways to solve this problem. The first one given that the 2 waves have the frequency then we know that the resultant wave amplitude is
Ym = (ym1 + ym2)cos(Ф_2/2)
By substitution we have
Ym= (0.025 + 0.045)cos(π/4) = 0.496 m
The second one is it treat them as Phasors where the phase between them is Ф_2=π / 2 Therefore
Ym^2=(ym1^2+ym2^2)
So we have Ym=√0.025^2+0.045^2
= 0.5 m
As velocities are tangent, the value of both Particle A and Particle B would be same for that point O (Intersecting point)
a = v / t
Here, v = 7, t = 6
So, a = 7/6
a = 1.17
As the graph is decreasing, value of acceleration would be negative.
So, a = -1.17 m/s²
In short, Your Answer would be Option C
Hope this helps!
<u>Given that</u>
mass (m) = 1300 Kg ,
height (h) = 1500 m
Determine the potential energy ?
P.E = m × g × h
= 1300 × 9.81 × 1500
= 19129500 Joules
= 19129.5 KJ
Answer: The final volume V₂ of the container is 0.039 m³.
Explanation:
Since the temperature is constant, the gas would expand isothermally.
For isothermal expansion,
P₁V₁=P₂V₂
Where, P₁ and P₂ are the initial and final pressure and V₁ and V₂ are initial and final volume.
It is given that:
V₁ = 0.0250 m³
P₁ = 1.5 × 10⁶ Pa
P₂ = 0.950 × 10⁶ Pa
V₂ = ?
⇒ 1.5 × 10⁶ Pa × 0.0250 m³ = 0.950 × 10⁶ Pa × V₂
⇒V₂ = 0.039 m³
Hence, the final volume V₂ of the container is 0.039 m³.
Answer:
D) 117 rad/s
Explanation:
We can treat this system as a circular motion where the origin is the elbow joint, the ball rotation velocity v is 35 m/s, the rotation radius is r = 0.3m.
As the ball is leaving the pitcher hand at such speed and rotation radius. Its angular velocity is:
