Answer:
18.5 m/s
Explanation:
On a horizontal curve, the frictional force provides the centripetal force that keeps the car in circular motion:
where
is the coefficient of static friction between the tires and the road
m is the mass of the car
g is the gravitational acceleration
v is the speed of the car
r is the radius of the curve
Re-arranging the equation,
And by substituting the data of the problem, we find the speed at which the car begins to skid:
Answer:
28√3 m
Explanation:
A = vertex where receiver is placed
S = focus
Bp = r = radius of the outside edge
Bc = 2r = diameter
The full explanation is shown in the picture attached herewith. Thank you and i hope it helps.
Answer:
We can conclude that there is a decrease in kinetic energy of the particles due to their elastic collision, since kinetic energy is directly proportional to squared velocity of the particles.
Explanation:
Given:
initial velocity of particle A, Ua = 5m/s
initial velocity of particle B, Ub = 10 m/s
final velocity of particle A, Va = 4m/s
final velocity of particle B, Vb = 7m/s
For particle A:
The final velocity is 1 less than the initial velocity.
For particle B:
The final velocity is 3 less than the initial velocity.
We can conclude that there is a loss in kinetic energy due to elastic collision of the two particles, since kinetic energy is directly proportional to squared velocity of the particles. A decrease in velocity means decrease in kinetic energy.
Answer:
The distance the planet Neptune travels in a single orbit around the Sun is <em>60.2π </em><em>AU.</em>
Explanation:
As it is given that the Neptune's orbit is circular, the formula that we have to use is the circumference of a circle in order to find the distance it travels in a single orbit around the Sun. In other words, you can say that the circumference of the circle is <em>equivalent</em> to the distance it travels around the Sun in a single orbit.
<em>The circumference of the circle = Distance Travelled (in a single orbit) = 2*π*R ---- (A)</em>
Where,
<em>R = Orbital radius (in this case) = 30.1 AU</em>
<em />
Plug the value of R in the equation (A):
<em>(A) => The circumference of the circle = 2*π*(30.1)</em>
<em> The circumference of the circle = </em><em>60.2π</em>
Therefore, the distance the planet Neptune travels in a single orbit around the Sun is <em>60.2π </em><em>AU.</em>
