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klemol [59]
2 years ago
9

On a ring road, 12 trams are spaced at regular intervals and travel at a constant speed. How many trams need to be added to the

circuit so that, maintaining the same speed, the intervals between them will decrease by 1 5
Physics
1 answer:
Sphinxa [80]2 years ago
4 0

3 trams must be added

Explanation:

In this problem, there are 12 trams along the ring road, spaced at regular intervals.

Calling L the length of the ring road, this means that the space between two consecutive trams is

d=\frac{L}{12} (1)

In this problem, we want to add n trams such that the interval between the trams will decrease by 1/5; therefore the distance will become

d'=(1-\frac{1}{5})d=\frac{4}{5}d

And the number of trams will become

12+n

So eq.(1) will become

\frac{4}{5}d=\frac{L}{n+12} (2)

And substituting eq.(1) into eq.(2), we find:

\frac{4}{5}(\frac{L}{12})=\frac{L}{n+12}\\\rightarrow n+12=15\\\rightarrow n = 3

Learn more about distance and speed:

brainly.com/question/8893949

#LearnwithBrainly

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Determine the centripetal force upon a 40-kg child who makes 10 revolution around the cliffhanger in 29.3 seconds.the radius of
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Answer:

The centripetal force acting on the child is 39400.56 N.

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Time taken for 10 revolutions is, t=29.3\ s

Therefore, the time period of the child is given as:

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Now, centripetal force acting on the child is given as:

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8 0
2 years ago
If a sound with frequency fs is produced by a source traveling along a line with speed vs. If an observer is traveling with spee
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Answer:

457.81 Hz

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As a result, we use this form

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vo = velocity of observer relative to source = 45 m/s

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fs = frequency of sound wave by source = 459 Hz

By substituting the the values to the equation, we have

fo = (332 + 45) / (332 - (-46)) × 459

fo = (377/ 332 + 46) × 459

fo = (377/ 378) × 459

fo = 0.9974 × 459

fo = 457.81 Hz

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Summary:
m=1kg
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I hope to help you

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