On a ring road, 12 trams are spaced at regular intervals and travel at a constant speed. How many trams need to be added to the
1 answer:
3 trams must be added
Explanation:
In this problem, there are 12 trams along the ring road, spaced at regular intervals.
Calling L the length of the ring road, this means that the space between two consecutive trams is
(1)
In this problem, we want to add n trams such that the interval between the trams will decrease by 1/5; therefore the distance will become
And the number of trams will become
So eq.(1) will become
(2)
And substituting eq.(1) into eq.(2), we find:
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Answer:
The acceleration of the rocket is 10 m/s².
Explanation:
Let the acceleration of the rocket be m/s².
Given:
Mass of the rocket is,
Thrust force acting upward is,
Acceleration due to gravity is,
Now, force acting in the downward direction is due to the weight of the rocket and is given as:
Now, net force acting on the rocket in upward direction is given as:
Therefore, from Newton's second law, net force acting on the rocket is equal to the product of mass and acceleration.
Therefore, the acceleration of the rocket is 10 m/s².
Answer:
(a) 0.0178 Ω
(b) 3.4 A
(c) 6.4 x 10⁵ A/m²
(d) 9.01 x 10⁻³ V/m
Explanation:
(a)
σ = Electrical conductivity = 7.1 x 10⁷ Ω-m⁻¹
d = diameter of the wire = 2.6 mm = 2.6 x 10⁻³ m
Area of cross-section of the wire is given as
A = (0.25) π d²
A = (0.25) (3.14) (2.6 x 10⁻³)²
A = 5.3 x 10⁻⁶ m²
L = length of the wire = 6.7 m
Resistance of the wire is given as
R = 0.0178 Ω
(b)
V = potential drop across the ends of wire = 0.060 volts
i = current flowing in the wire
Using ohm's law, current flowing is given as
i = 3.4 A
(c)
Current density is given as
J = 6.4 x 10⁵ A/m²
(d)
Magnitude of electric field is given as
E = 9.01 x 10⁻³ V/m