Answer:
Two identical spheres are released from a device at time t = 0 from the same ... Sphere A has no initial velocity and falls straight down. ... (b) On the axes below, sketch and label a graph of the horizontal component of the velocity of sphere A and of sphere B as a function of time. ... Which ball has the greater vertical velocity
Explanation:
Answer:
ΔE = 8.77 × 10¹¹ J
Explanation:
given,
²¹⁴₈₄Po -----> ²¹⁰₈₂Pb + 42 He
Atomic masses: Pb-210 = 209.98284 amu
Po-214 = 213.99519 amu
He-4 = 4.00260 amu
1 kg = 6.022 × 10²⁶ amu;
NA = 6.022 × 10²³ mol⁻¹
c = 2.99792458 × 10⁸ m/s
energy of molecule using equation
ΔE = Δm c²
Δm is mass difference and c is speed of light
Δm = 209.98284 + 4.00260 - 213.99519
Δm = - 0.00975 amu
1 amu = 1.66 x 10⁻²⁷ kg
- 0.00975 amu = - 0.00975 x 1.66 x 10⁻²⁷ Kg
= -0.016185 x 10⁻²⁷ Kg
total mass = 6.022 × 10²³ x -0.016185 x 10⁻²⁷
= -0.097467 x 10⁻⁴ Kg
ΔE = -(0.097467 x 10⁻⁴) (3 x 10^8)²
ΔE = - 8.77 × 10¹¹
ΔE = 8.77 × 10¹¹ J
Answer:
The mass of the cube is 420.8 kg.
Explanation:
Given that,
Length of edge = 38.9 cm
Density 
We need to calculate the volume of cube
Using formula of volume
We need to calculate the mass of the cube
Using formula of density
Hence, The mass of the cube is 420.8 kg.
Potential energy at any point is (M G H). On the way down, only H changes. So halfway down, half of the potential energy remains, and the other half has turned to kinetic energy. Half of the (M G H) it had at the tpp is (0.5 x 9.8 x 10) = 49 joules.
Answer:
P_(pump) = 98,000 Pa
Explanation:
We are given;
h2 = 30m
h1 = 20m
Density; ρ = 1000 kg/m³
First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,
Thus, it can be expressed as;
P_(tank)+ P_(pump) = P_(nozzle)
Now, the pressure would be given by;
P = ρgh
So,
ρgh_1 + P_(pump) = ρgh_2
Thus,
P_(pump) = ρg(h_2 - h_1)
Plugging in the relevant values to obtain;
P_(pump) = 1000•9.8(30 - 20)
P_(pump) = 98,000 Pa
