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natka813 [3]
2 years ago
5

An overhead projector lens is 32.0 cm from a slide (the object) and has a focal length of 30.1 cm. What is the magnification of

the image? PLS HELP
Physics
1 answer:
puteri [66]2 years ago
6 0

Answer: 15.8

Explanation:

You are given that the

Object distance U = 32 cm

Focal length F = 30.1 cm

First calculate the image distance V by using the formula

1/F = 1/U + 1/V

Substitute F and V into the formula

1/30.1 = 1/32 + 1/V

1/V = 1/30.1 - 1/32

1/V = 0.00197259

Reciprocate both sides

V = 506.94 cm

Magnification M is the ratio of image distance to object distance.

M = V/U

substitute the values of V and U into the formula

M = 506.94/32

M = 15.8

Therefore, the magnification of the image is 15.8 or approximately 16.

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2 years ago
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The force sensor measures the force on the sensor due to the bumper, but the cart's momentum change arises from the force on the
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Answer:

Answered

Explanation:

1 and 3 are necessary

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2 years ago
If you touch the two terminals of a power supply with your two fingertips on opposite hands, the potential difference will produ
LiRa [457]

Answer:

Yes the body will receive a dangerous shock in both cases.

Explanation:

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Dry skin has high resistance than wet skin this is because water is relatively good conductor of electricity, it adds parallel path to the current flow and hence reduces skin resistance.

Dry hands body has approximately 500 kΩ resistance and if 120 V electricity supply current received will be:

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Similarly for wet hands body resistance is 1 kΩ. so the current through the body seems to be:

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7 0
2 years ago
A force of 6.0 N pulls a box 0.40 m along a frictionless plane that is inclined at 36°. What work is being done by the pulling f
lys-0071 [83]

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here we know that

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so we will have

W = 6 \times 0.4 cos36

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