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2 years ago

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Sachi wants to throw a water balloon to knock over a target and win a prize. The target will only fall over if it is hit with a

force of 0.035 N. The water balloon has a mass of 11.4 grams. How fast will Sachi have to make the water balloon accelerate to hit the target with enough force and win the prize?

2 answers:

Verizon [17]2 years ago

8 0

3.1 the only reason i know this is cause i got it wrong

Mashutka [201]2 years ago

8 0

Remember that acceleration (a) equals force (F) over mass (m) or a=F/m. In this equation, both the force, 0.035N, and the mass, 11.4 grams, are provided. However, the mass is provided in the wrong unit, as it should be calculated in kilograms. To set up this equation, you will have to convert 11.4 grams into .0114 kilograms then divide .035 N over 0.114 kg to get your answer of 3.07 m/s^2 rounded to 3.1 m/s^2

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ehidna [41]

Answer

The Value of r = 0.127

Explanation:

The mathematical representation of the two resistors connected in series is

$R_T = R_1 +R_2$

And from Ohm law

$I_s =\frac{ V}{R_T}$

$I_s = \frac{V_0}{R_1 +R_2} ---(1)$

The mathematical representation of the two resistors connected in parallel is

$R_T = \frac{1}{R_1} +\frac{1}{R_2}$

$= \frac{R_1 R_2}{R_1 +R_2}$

From the question $I_p =10I_s$

=> $I_p =10I_s = \frac{V_0 }{\frac{R_1R_2}{R_1 +R_2} } = \frac{V_0 (R_1 +R_2)}{R_1 R_2}---(2)$

Dividing equation 2 with equation 1

=> $\frac{10I_s}{I_s} =\frac{\frac{V_0 (R_1 +R_2)}{R_1 R_2}}{\frac{V_0}{R_1 +R_2}}$

$10 = \frac{(R_1+R_2)^2}{R_1 R_2}----(3)$

We are told that $r = \frac{R_1}{R_2} \ \ \ \ \ = > R_1 = rR_2$

From equation 3

$10 = \frac{(1-r)^2}{r}$

$=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1+r^2 + 2r = 10r$

$=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ r^2 -8r+1 = 0$

Using the quadratic formula

$r =\frac{-b\pm \sqrt{(b^2 - 4ac)} }{2a}$

a = 1 b = -8 c =1

$= \frac{8 \pm\sqrt{((-8)^2- (4*1*1))} }{2*1}$

$r= \frac{8+ \sqrt{60} }{2} \ or \ r = \frac{8 - \sqrt{60} }{2}$

$r = \ 7.87\ or \ r \ = \ 0.127$

Now r = 0.127 because it is the least value among the obtained values

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SIZIF [17.4K]

Answer:

$5.45\times 10^{-4}$ W

Explanation:

$T_{r}$ = Temperature of the room = 22.0 °C = 22 + 273 = 295 K

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$\epsilon$ = emissivity = 0.97

$\sigma$ = Stefan's constant = 5.67 x 10⁻⁸ Wm⁻² K⁻⁴

Rate of heat transfer is given as

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Annette [7]

Jogger moves in three displacements

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now we can say

total displacement towards East direction will be

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$d_y = 5 block$

now to find the net displacement we can use vector addition

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$d = \sqrt{12^2 + 5^2}$

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<em>so magnitude of net displacement will be equal to 13 blocks</em>

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Explanation:

It is given that,

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Speed, $v=5\times 10^{6}\ m/s$

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B = 0.004 T

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B = 4 mT

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Alecsey [184]

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