Sachi wants to throw a water balloon to knock over a target and win a prize. The target will only fall over if it is hit with a
2 answers:
You might be interested in
Answer:
82.76m
Explanation:
In order to find the distance of the steel ring to the ground, when its temperature has raised by 1°C, you first calculate the radius of the steel tube before its temperature increases.
You use the formula for the circumference of the steel ring:
(1)
C: circumference of the ring = 40000 km = 4*10^7m (you assume the circumference is the length of the steel tube)
you solve for r in the equation (1):
Next, you use the following formula to calculate the change in the length of the tube, when its temperature increases by 1°C:
(2)
L: final length of the tube = ?
Lo: initial length of the tube = 4*10^7m
ΔT = change in the temperature of the steel tube = 1°C
α: thermal coefficient expansion of steel = 13*10^-6 /°C
You replace the values of the parameters in the equation (2):
With the new length of the tube, you can calculate the radius of a ring formed with the tube. You again solve the equation (1) for r:
Finally, you compare both r and r' radius:
r' - r = 6,366,280.484m - 6,366,197.724m = 82.76m
Hence, the distance to the ring from the ground is 82.76m
Answer:
The moun lives 2.198*10^-6 s as measured by its own frame of reference
The Earth moved 648 m as measured by the moun's frame of reference
Explanation:
From the point of view of the observer on Earth the muon traveled 3.53 km at 0.983c
0.983 * 3*10^8 = 2.949*10^8 m/s
Δt = d/v = 3530 / 2.949*10^8 = 1.197*10^-5 s
The muon lived 1.197*10^-5 s from the point of view of the observer.
The equation for time dilation is:
Then:
From the point of view of the moun Earth moved at 0.983c (2.949*10^8 m/s) during a time of 2.198*10^-6, so it moved
d = v*t = 2.949*10^8 * 2.198*10^-6 = 648 m