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timama [110]
2 years ago
5

A 60 kilogram astronaut weighs 96 newtons on the surface of the moon. calculate the acceleration due to gravity on the moon.

Physics
2 answers:
Charra [1.4K]2 years ago
8 0

Answer:

Acceleration due to gravity on moon, 1.6\ m/s^2

Explanation:

Mass of the astronaut, m = 60 kg

Weight of astronaut on the surafce of moon, W = 96 N

The weight of astronaut is given by :

W = m g

g=\dfrac{W}{m}

g=\dfrac{96\ N}{60\ kg}

g=1.6\ m/s^2

So, the acceleration due to gravity on the surface of moon is 1.6\ m/s^2

Also, the acceleration due to gravity on the surface of moon is (1/6)th of the acceleration due to gravity on the surface of earth.

Hence, this is the required solution.

34kurt2 years ago
6 0
Given: Mass m = 60 Kg

           Weight  W = 96 N

Required: Acceleration due to gravity, g = ?

Formula:  W = mg

                g = W/g

                g = 96 Kg.m/s²/60 Kg   (note: this is the derive unit for Newton "N")

                g = 1.6 m/s²

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(Double points) A machine receives electricity that enables it to deliver a total of 8,542 N of force for the completion of its
storchak [24]

Answer: machine's efficiency = 82.2%

Explanation:

Efficiency of a machine is the capability of a machine to convert input to output without waste.

It can be expressed as

Efficiency = output/ input × 100%

Output = 7,023N

Imput = 8,542N

Efficiency = 7,023N/8,542N × 100%

Efficiency = 82.2%

4 0
2 years ago
The statements below are all true. Some of them represent important reasons why the giant impact hypothesis for the Moon’s forma
Molodets [167]

Answer:

the order of importance must be     b e a f c

Explanation:

Modern theories indicate that the moon was formed by the collision of a bad plant with the Earth during its initial cooling period, due to which part of the earth's material was volatilized and as a ring of remains that eventually consolidated in Moon.

Based on the aforementioned, let's analyze the statements in order of importance

b) True. Since the moon is material evaporated from Earth, its compassion is similar

e) True. If the moon is material volatilized from the earth it must train a finite receding speed

a) True. The solar system was full of small bodies in erratic orbits that wander between and with larger bodies

f) False. The moon's rotation and translation are equal has no relation to its formation phase

c) false. The amount of vaporized material on the moon is large

Therefore, the order of importance must be

         b e a f c

5 0
2 years ago
An airliner of mass 1.70×105kg1.70×105kg lands at a speed of 75.0 m/sm/s. As it travels along the runway, the combined effects o
Karo-lina-s [1.5K]

Answer:

The airliner travels 1.65 km along the runway before coming to a halt.

Explanation:

Given

Resistive forces = (2.90 × 10⁵) N = 290000 N

Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg

Velocity of airliner = 75 m/s

Let the distance over moved by the airliner be equal to d

According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.

Work done by the resistive forces = (290000) × d = (290,000d) J

Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J

290000d = 478,125,000

d = (478,125,000/290,000)

d = 1648.7 m = 1.65 km

Hope this helps!!!

4 0
2 years ago
For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser poin
nydimaria [60]

Answer:

The width of slide is 0.092 mm.

Explanation:

Given that,

Wave length = 680 nm

Distance between slit and screen D= 5.4 m

Distance of bright band 2y = 7.9 cm

y =\dfrac{7.9}{2}

y=3.95\ cm

We need to calculate the width of slide

Using formula of width

d=\dfrac{\lambda D}{y}

Where, d = width

D =Distance between slit and screen

y = Distance of bright band

Put the value into the formula

d=\dfrac{680\times10^{-9}\times5.4}{3.95\times10^{-2}}

d=0.092\times10^{-3}\ m

d=0.092\ mm

Hence, The width of slide is 0.092 mm.

4 0
2 years ago
Bianca is standing at x =600m. Firecracker 1, at the origin, and firecracker 2, at x =900m, explode simultaneously. The flash fr
agasfer [191]

Answer:3 \mu s

Explanation:

Given

Bianca is at x=600 m

i.e. distance between origin and Bianca is 600 m

time taken to reach Bianca eyes is

t=\frac{600}{speed\ of\ light}

t=\frac{600}{3\times 10^8}

t=2\times 10^{-6} s

t=2 \mu s

i.e. Cracker exploded at t=2\mu s because it is observed at t=4\mu s

Time taken by second cracker flash to reach Bianca eyes

t_2=\frac{300}{3\times 10^8}

t_2=10^{-6}

t_2=1 \mu s

Therefore it will be observed at t=3 \mu s

4 0
2 years ago
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