Given :
Displacement , y = 0.75 m .
Angular acceleration , .
Initial angular velocity , .
To Find :
The value of vertical velocity after time t = 0.25 s .
Solution :
By equation of circular motion is given by :
Putting all given values we get :
Now , vertical velocity is given by :
Therefore , the numerical value of the vertical velocity of the car at time t=0.25 s is 4.90 m/s .
Hence , this is the required solution .
To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as
Where,
F = Force/Weight
A = Area
= Compression
= Original Length
According to the values given we have to
Replacing this values at our previous equation we have,
Therefore the Weight of the object is 3.82kN
Answer:
The tension in the rope is 229.37 N.
Explanation:
Given:
Mass of the block is,
Coefficient of static friction is,
Angle of inclination is, °
Draw a free body diagram of the block.
From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.
Forces acting are and normal
. Now, there is no motion in the direction perpendicular to the inclined plane. So,
Consider the direction along the inclined plane.
The forces acting along the plane are and frictional force,
, down the plane and tension,
, up the plane.
Now, as the block is at rest, so net force along the plane is also zero.
Therefore, the tension in the rope is 229.37 N.
Answer:
0.0000045 s
Explanation:
f = Frequency = 8 MHz
Clock cycle is given by
Time taken for 12 clock cycles
Time taken per instruction is 0.0000015 s
In reading and displaying information it requires 3 processes
1 for reading, 1 for searching and 1 for displaying.
Time taken is 0.0000045 s