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skad [1K]
2 years ago
14

How much does a person weigh if it takes 700 kg*m/s to move them 10 m/s NEED ASAP

Physics
1 answer:
madreJ [45]2 years ago
5 0

Answer:

\huge\boxed{m = 70 \ kg}

Explanation:

<u>Given Data:</u>

Momentum = P = 700 kg m/s

Velocity = v = 10 m/s

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

P = mv

<u>Solution:</u>

m = P / v

m = 700 / 10

m = 70 kg

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
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Setler [38]

Answer:

given,

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Q = 11153.63 J

He required

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Q = 2788.41 J

He required

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2788.41 = m × 2700

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8 0
2 years ago
A heavy frog and a light frog jump straight up into the air. They push off in such away that they both have the same kinetic ene
Ilia_Sergeevich [38]

Answer:

The lighter frog goes higher than the heavier frog.

The lighter frog is moving faster than the heavier frog

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If both frogs have the same kinetic energy when they leave the ground, the following equality applies:

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Now, if the only force acting on the frogs is gravity, when they reach to the maximum height, we can apply the following kinematic equation:

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When h= hmax, the object comes momentarily to an stop, so vf =0

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hmax =\frac{vo^{2} }{2*g}

As the lighter frog, in order to have the same kinetic energy than the heavier one, has a greater initial velocity, it will go higher than the other.

As a consequence of both having the same kinetic energy, the lighter frog will be moving faster than the heavier frog.

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What physical property of minerals describes how they will break along a plane of weakness in a crystal lattice?
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Flauer [41]

Answer:

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2 years ago
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