Question

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 2750 2750 Newtons while Magnus pulls the bus a distance of 1.60 1.60 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.

Answer 1

Answer:

The workdone is  $W_d =-4400J$

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

            The force is on the force gauge  $F = 2750 N$

             The distance that Magnus pulled the bus  $d = 1.60m$

Generally  the workdone by the tension force on Magnus is

                  $Workdone = Force * displacement \ in \ the \ direction \ of \ force$

                     $W_d = F * (-d)$

This negative sign show that is tension force  is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

                   $Workdone = - 2750 * 1.60$

                                     $=-4400 J$