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Gelneren [198K]
2 years ago
5

A basketball player makes a jump shot. The 0.600-kg ball is released at a height of 2.01 m above the floor with a speed of 7.26

m/s. The ball goes through the net 3.10 m above the floor at a speed of 3.81 m/s. What is the work done on the ball by air resistance, a nonconservative force
Physics
1 answer:
matrenka [14]2 years ago
7 0

Answer: Work done on the ball by air resistance = -5.049J

Explanation:

From law of conservation of energy

Potential energy + kinetic energy + Work of air resistance  = Potential energy + kinetic energy +

mgh + 1/2 mv^2  + W= mgh¹ + 1/2 mv¹^2

=0.6 Kg x 9.8m/s x 2.01  +1/2 x0.60 x (7.26)^2+ W= 0.6 x 9.8 x 3.10 + 1/2 x 0.6 x 3.81

=11.8188 + 15.81288 +W = 18.228 + 4.3548

=27.63168 +W =22.58283

W = 22.578-27.63168

W=-5.049 J

Work done on the ball by air resistance = -5.049J ( N egative sign indicates that  Work was in opposite direction of motion

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A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along
storchak [24]

Answer:

v = \frac{kQ}{a}  

Explanation:

We define the linear density of charge as:

\lambda = \frac{Q}{L}

     Where L is the rod's length, in this case the semicircle's length L = πr

The potential created at the center by an differential element of charge is:

dv = \frac{kdq}{r}

          where k is the coulomb's constant

                     r is the distance from dq to center of the circle

Thus.

v = \int_{}^{}\frac{kdq}{a}  

v = \frac{k}{a}\int_{}^{}dq

v = \frac{kQ}{a}     Potential at the center of the semicircle

4 0
2 years ago
A quantity y is to be determined from the equation y=(px)/q^2
ki77a [65]

Answer:

heya answer option b

Explanation:

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4 0
2 years ago
A 5.00-kg ball is hanging from a long but very light flexible wire when it is struck by a 1.50-kg stone traveling horizontally t
devlian [24]

consider the right direction as positive and left direction as negative.

M = mass of the ball = 5 kg

m = mass of stone = 1.50 kg

V_{bi} = initial velocity of the ball before collision = 0 m/s

V_{si} = initial velocity of the stone before collision = 12 m/s

V_{bf} = final velocity of the ball after collision = ?

V_{sf} = final velocity of the stone after collision = - 8.50 m/s

using conservation of momentum

MV_{bi} + mV_{si} = MV_{bf} + mV_{sf}

(5) (0) + (1.5) (12) = 5 V_{bf} + (1.50) (- 8.50)

V_{bf} = 6.15 m/s

h = height gained by the ball

using conservation of energy

Potential energy gained by ball at Top = kinetic energy at the bottom

Mgh = (0.5) MV_{bf}^{2}

(9.8) h = (0.5) (6.15)²

h = 1.93 m

8 0
2 years ago
Read 2 more answers
A car travels 10 m/s east. Another car travels 10 m/s north. The relative speed of the first car with respect to the second is:
Thepotemich [5.8K]

Answer:

d. less than 20m/s

Explanation:

To the 2nd car, the first car is travelling 10m/s east and 10m/s south. So the total velocity of the first car with respect to the 2nd car is

[tex]\sqrt{10^2 + 10^2} =10\sqrt{2}=14.14m/s

As 14.14m/s is less than 20m/s. d is the correct selection for this question.

3 0
2 years ago
For a Physics course containing 10 students, the maximum point total for the quarter was 200. The point totals for the 10 studen
Talja [164]

Answer:

130.5

Explanation:

According to the stemplot attached (Which I think it is, and if not, then you only need to replace the procedure with your data and you should be fine), you need to calculate first the points of all ten students. In that plot, we can easily calculate the points.

The first number in the colum represents the centen of the point, while the numbers of the second column, represents the units of that centen, for example if you see:

16 | 8 5 6

This means that the point for the students are 168, 165 and 166. Three students, three points.

If you watch the stemplot, the points for the students are:

116, 118, 121, 124, 128, 133, 137, 142, 146 and 179.

The median can be calculated using the mean between the two values in the middle of the sequence.

In this case, half of ten is 5, so, the numbers from the middle in this sequence are 128 and 133, therefore:

Median = 128 + 133 / 2 = 130.5

5 0
2 years ago
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