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2 years ago

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A shell is ﬁred from the ground with an initial speed of 1.70x10^3 m/s at an initial angle of 55.0° to the horizontal, Neglectin

g air resistance, what is the shell's horizontal range and the amount of time the shell is in motion?

1 answer:

Ede4ka [16]2 years ago

4 0

Answer:

range = 276.8 km, time = 142 s

Explanation:

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A professor's office door is 0.99 m wide, 2.2 m high, 4.2 cm thick; has a mass of 27 kg, and pivots on frictionless hinges. A "d

ANEK [815]

Answer:

$I=8.8209\ kg.m^2$

$\alpha=0.6348\ rad.s^{-2}$

Explanation:

Given:

width of door, $w=0.99\ m$

height of the door, $h=2.2\ m$

thickness of the door, $t=4.2\ cm$

mass of the door, $m=27\ kg$

torque on the door, $\tau=5.6\ N.m$

<em>∵Since the thickness of the door is very less as compared to its other dimensions, therefore we treat it as a rectangular sheet.</em>

For a rectangular sheet we have the mass moment of inertia inertia as:

$I=\frac{1}{3} m.w^2$

$I=\frac{1}{3}\times 27\times 0.99^2$

$I=8.8209\ kg.m^2$

We have a relation between mass moment of inertia, torque and angular acceleration as:

$\alpha=\frac{\tau}{I}$

$\alpha=\frac{5.6}{8.8209}$

$\alpha=0.6348\ rad.s^{-2}$

6 0

2 years ago

Complete the statements using data from Table A of your Student Guide. The speed of the cart after 8 seconds of Low fan speed is

finlep [7]

Answer:

The speed of the cart after 8 seconds of Low fan speed is 72.0 cm/s

The speed of the cart after 3 seconds of Medium fan speed is 36.0 cm/s

The speed of the cart after 6 seconds of High fan speed is 96.0 cm/s

Explanation:

took the test on edgenuity

4 0

1 year ago

Read 2 more answers

Drying of Cassava (Tapioca) Root. Tapioca flour is used in many countries for bread and similar products. The flour is made by d

svet-max [94.6K]

Yea it would be 500 minus 10 is 490

5 0

1 year ago

A system contains a perfectly elastic spring, with an unstretched length of 20 cm and a spring constant of 4 N/cm.

mote1985 [20]

Answer:

a) When its length is 23 cm, the elastic potential energy of the spring is

0.18 J

b) When the stretched length doubles, the potential energy increases by a factor of four to 0.72 J

Explanation:

Hi there!

a) The elastic potential energy (EPE) is calculated using the following equation:

EPE = 1/2 · k · x²

Where:

k = spring constant.

x = stretched lenght.

Let´s calculate the elastic potential energy of the spring when it is stretched 3 cm (0.03 m).

First, let´s convert the spring constant units into N/m:

4 N/cm · 100 cm/m = 400 N/m

EPE = 1/2 · 400 N/m · (0.03 m)²

EPE = 0.18 J

When its length is 23 cm, the elastic potential energy of the spring is 0.18 J

b) Now let´s calculate the elastic potential energy when the spring is stretched 0.06 m:

EPE = 1/2 · 400 N/m · (0.06 m)²

EPE = 0.72 J

When the stretched length doubles, the potential energy increases by a factor of four to 0.72 J

7 0

2 years ago

The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope. The sl

KonstantinChe [14]

Answer:

Acceleration, $a=1.2\ m/s^2$

Explanation:

Given that,

The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope, m = 100 kg

Force exerted by the doges on the rope attached to the front sled, F = 240 N

To find,

The acceleration of the sleds.

Solution,

Let a is the acceleration of the sleds. The product of mass and acceleration is called force. Its expression is given by :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{240\ N}{2\times 100\ kg}$ (m = 2m)

$a=1.2\ m/s^2$

So, the acceleration of the sleds is $1.2\ m/s^2$ .

6 0

2 years ago