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Sever21 [200]
2 years ago
10

A shell is fired from the ground with an initial speed of 1.70x10^3 m/s at an initial angle of 55.0° to the horizontal, Neglectin

g air resistance, what is the shell's horizontal range and the amount of time the shell is in motion?

Physics
1 answer:
Ede4ka [16]2 years ago
4 0

Answer:

range = 276.8 km, time = 142 s

Explanation:

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zzz [600]

Answer:

h=20.66m

Explanation:

First we need the speed when the cord starts stretching:

V_2^2=V_o^2-2*g*\Delta h

V_2^2=-2*10*(-31)

V_2=24.9m/s   This will be our initial speed for a balance of energy.

By conservation of energy:

m*g*h+1/2*K*(h_o-l_o-h)^2-m*g*(h_o-l_o)-1/2*m*V_2^2=0

Where

h is your height at its maximum elongation

h_o is the height of the bridge

l_o is the length of the unstretched bungee cord

800h+21*(79-h)^2-63200-24800.4=0

21h^2-2518h+43060.6=0 Solving for h:

h_1=20.66m  and h_2=99.24m  Since 99m is higher than the initial height of 79m, we discard that value.

So, the final height above water is 20.66m

6 0
2 years ago
Read 2 more answers
Why do charges build up on clothing in an electric dryer?
Rzqust [24]
Charges build up when you have dry air  and friction ,the heat to clothes which dry it out and causes friction.
4 0
2 years ago
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Light from a monochromatic source shines through a double slit onto a screen 5.00 m away. The slits are 0.180 mm apart. The dark
Nitella [24]

Answer:

Wavelength of incident light, \lambda = 612 nm

Given:

Distance between slit and screen, x = 5.00 m

slit width, d = 0.180 mm

width of the fringe, \beta = 1.70 cm = 0.017 m

Solution:

To calculate the wavelength of the incident light, \lambda:

\beta = \frac{x\lambda }{d}

\lambda = \frac{\beta d}{x}

\lambda = \frac{0.017\times 0.180\times 10^{- 3}}{5} = 6.12\times 10^{- 7}m = 612 nm

\lambda = 612 nm

4 0
2 years ago
A metal ball with diameter of a half a centimeter and hanging from an insulating thread is charged up with 1010 excess electrons
liraira [26]

When the metals touch together, half the charge of the charged metal flows to the other because the electrons all repel each other. Therefore this also means that each metal ball contains the same amount of electrons. Each ball has 5^10 electrons, this is equivalent to a total charge of:

Q1 = Q2 = (1.602 * 10^-19 coulombs / electron) 5^10 electrons = Q

Q = 1.564 * 10^-12 C

 

Now using the Coulombs law to find for the electric force:

F = k q1 q2 / r^2 = k (Q)^2 / r^2

where k is a contant = 9 * 10^9 N m^2 / C^2

r = the distance of the two metals = 0.2 m

So,

F = (9 * 10^9 N m^2 / C^2) (1.564 * 10^-12 C)^2 / (0.2 m)^2

F = 5.51 * 10^-13 N

 

Since the two metals repel therefore they are the one which exerts the force hence the magnitude must be negative:

<span>F = - 5.51 * 10^-13 N</span>

7 0
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Ugo [173]

Answer:

Explanation:D

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2 years ago
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