Answer:
Ft
Explanation:
We are given that
Initial velocity=u=0
We have to find the magnitude of p of the momentum of the particle at time t.
Let mass of particle=m
Applied force=F
Acceleration,
Final velocity ,
Substitute the values
We know that
Momentum, p=mv
Using the formula
Answer:
Isothermal : P2 = ( P1V1 / V2 ) , work-done
Adiabatic : : P2 = , work-done =
W =
Explanation:
initial temperature : T
Pressure : P
initial volume : V1
Final volume : V2
A) If expansion was isothermal calculate final pressure and work-done
we use the gas laws
= PIVI = P2V2
Hence : P2 = ( P1V1 / V2 )
work-done :
B) If the expansion was Adiabatic show the Final pressure and work-done
final pressure
where y = 5/3
hence : P2 =
Work-done
W =
Where
Answer:
the ratio is
Explanation:
Given
The RMS velocity of molecules in a gas is given by
where T=temperature
For T = 387K
For T = 774
dividing eqn 1 and eqn 2
Thus,the ratio is
Answer:
Connect C₁ to C₃ in parallel; then connect C₂ to C₁ and C₂ in series. The voltage drop across C₁ the 2.0-μF capacitor will be approximately 2.76 volts.
.
Explanation:
Consider four possible cases.
<h3>Case A: 12.0 V.</h3>In case all three capacitors are connected in parallel, the capacitor will be connected directed to the battery. The voltage drop will be at its maximum: 12 volts.
In case the capacitor is connected in parallel with the
capacitor, and the two capacitors in parallel is connected to the
capacitor in series.
The effective capacitance of two capacitors in parallel is the sum of their capacitance: 2.0 + 1.5 = 3.5 μF.
The reciprocal of the effective capacitance of two capacitors in series is the sum of the reciprocals of the capacitances. In other words, for the three capacitors combined,
.
What will be the voltage across the 2.0 μF capacitor?
The charge stored in two capacitors in series is the same as the charge in each capacitor.
.
Voltage is the same across two capacitors in parallel.As a result,
.
.
Similarly,
Charge stored:
.
Voltage:
.
.
Connect all three capacitors in series.
.
For each of the three capacitors:
.
For the capacitor:
.
