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2 years ago

Unit of work is derived unit why

1 answer:

3 0

The unit for work J can also be written as Nm. Therefore, it is a derived unit as different SI units are needed to obtain its value. In this case, its derived from force and distance.

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An elephant's legs have a reasonably uniform cross section from top to bottom, and they are quite long, pivoting high on the ani

PilotLPTM [1.2K]

Answer:

t = 6,485 s , t_step = 25.94 s

the elephant gives 2.3 step very minute

Explanation:

Let's approximate this system to a simple pendulum that has angular velocity

w = √L / g

Angular velocity and period are related

w = 2π / T

T = 2π √g / L

Let's find the period

T = 2π √9.8 / 2.3

T = 12.97 s

Stride time is

t = T / 2

t = 12.97 / 2

t = 6,485 s

Frequency is inversely proportional to period

f = 1 / t

f = 1 / 6,485

f = 0.15 Hz

Since the elephant has 4 legs and each uses a time t, the total time for one step is

t_step = 4 t

t_step = 4 6.485

t_step = 25.94 s

f_step = 1/t_step =0.0385 s-1

Now let's use a proportion rule to find the number of steps in 60 s

#_step = 60 / t_step

#__step = 60 / 25.94

#_step = 2.3 steps

So the elephant gives 2.3 step very minute

4 0

2 years ago

In an experiment, students release a block from rest at the top of an inclined plane. The block slides down the plane through a

mote1985 [20]

Answer:

B) Friction

Explanation:

The main source of error is the omission of the effect from friction between block and incline, which is directly proportional to the mass of the block. The force of gravity is constant. The friction force dissipates part of the gravitational potential energy, generating a final speed less than calculated under the consideration of a conservative system. Air resistance is neglected at low speeds like this case.

8 0

2 years ago

In 2014, the Rosetta space probe reached the comet Churyumov Gerasimenko. Although the comet's core is actually far from spheric

Viktor [21]

To solve this problem we will apply the concepts related to gravity according to the Newtonian definitions. From finding this value we will use the linear motion kinematic equations to find the time. Our values are

Comet mass $M = 1.0*10^{13} kg$

Radius $r = 1.6km = 1600 m$

Rock was dropped from a height 'h' from surface = 1m

The relation for acceleration due to gravity of a body of mass 'm' with radius 'r' is

$g = \frac{GM}{R^2}$

Where G means gravitational universal constant and M the mass of the planet

$g = \frac{(6.67408*10^{-11})(1*10^{13})}{1600^2}$

$g = 2.607*10^{-4} m/s^2$

Now calculate the value of the time

$h = \frac{1}{2} gt^2$

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2(1)}{2.607*10^{-4}}}$

$t = 87.58s$

The time taken for the rock to reach the surface is t = 87.58s

8 0

2 years ago

A 6000 kg lorry is reversing into a parking space at a speed of 0.5 m/s but collides with a car. The crumple zone of the car sto

zysi [14]

Answer:

3000 kg.m/s

Explanation:

Momentum, p is a product of mass and velocity hence

p=mv where m is mass and v is velocity.

Change in momentum is given by $m(v_f-v_i)$ where subscripts f and i represent final and initial respectively. Since the lorry finally comes to rest then the final velocity is zero. Substituting the given figures then

Change in momentum= 6000(0-0.5)=-3000 kg.m/s

7 0

2 years ago

The image shows a pendulum that is released from rest at point A. Shari tells her friend that no energy transformation occurs as

Masja [62]

Is D the right answer

6 0

2 years ago

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Unit of work is derived unit why​

Unit of work is derived unit why