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1 year ago

Paano nakatulong ang estratehikong lokasyon ng Pilipinas sa paghubog ng ating kasayasayan?

Physics

1 answer:

dangina [55]1 year ago

6 0

Answer:

wow sa Canada pa talaga nagtanong btw answer ko ayy

Kasaysayan ng Pilipinas

Kasaysayan ng PilipinasAng Pilipinas ay isang bansa na makikita sa timog-silangang Asya at malapit sa dagat Pasipiko. Ito ay binubuo ng mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:

mahigit sa 7000 na isla, at nagsisilbing tirahan para sa mga Pilipino. Ang mga sumusunod ay ilan lamang sa mga paraan kung paanong nakatulong ang estratehikong lokasyon ng ating bansa sa pagbuo ng ating kasaysayan:Dahil tayo ay napalilibutan ng anyong tubig, pangingisda ang naging pangunahing pamumuhay ng mga sinaunang Pilipino.Noong naglayag si Ferdinand Magellan, siya ay napunta sa isa sa mga isla sa Pilipinas. Ito ang naging simula ng kolonisasyonDahil sa estratehikonglo

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Answer:

Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.1×109 electrons from one disk to the other causes the electric field strength between them to be 1.6×105 N/C. What are the diameters of the disks?

Explanation:

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2 years ago

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The rotational speeds of four generators are listed in RPM (revolutions per minute). Arrange the generators in order based on th

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Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and

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Answer: One canister contains 1.03 Kg of fuel,

Explanation:

The density is defined as the relation between the mass and the volume $p=\frac{m}{v}$

First of all you need to have the same units for volume and density, so:

For the volume,

$1.45 L * \frac{1.10*10^{-3}m^{3} }{1 L} = 1.45 *10^{-3} m^{3}$

For the density,

$p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3} }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }$

From the density equation we have $m=p*v$ , so:

$710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg$

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2 years ago

Consider an object with s=12cm that produces an image with s′=15cm. Note that whenever you are working with a physical object, t

Leni [432]

A. 6.67 cm

The focal length of the lens can be found by using the lens equation:

$\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}$

where we have

f = focal length

s = 12 cm is the distance of the object from the lens

s' = 15 cm is the distance of the image from the lens

Solving the equation for f, we find

$\frac{1}{f}=\frac{1}{12 cm}+\frac{1}{15 cm}=0.15 cm^{-1}\\f=\frac{1}{0.15 cm^{-1}}=6.67 cm$

B. Converging

According to sign convention for lenses, we have:

- Converging (convex) lenses have focal length with positive sign

- Diverging (concave) lenses have focal length with negative sign

In this case, the focal length of the lens is positive, so the lens is a converging lens.

C. -1.25

The magnification of the lens is given by

$M=-\frac{s'}{s}$

where

s' = 15 cm is the distance of the image from the lens

s = 12 cm is the distance of the object from the lens

Substituting into the equation, we find

$M=-\frac{15 cm}{12 cm}=-1.25$

D. Real and inverted

The magnification equation can be also rewritten as

$M=\frac{y'}{y}$

where

y' is the size of the image

y is the size of the object

Re-arranging it, we have

$y'=My$

Since in this case M is negative, it means that y' has opposite sign compared to y: this means that the image is inverted.

Also, the sign of s' tells us if the image is real of virtual. In fact:

- s' is positive: image is real

- s' is negative: image is virtual

In this case, s' is positive, so the image is real.

E. Virtual

In this case, the magnification is 5/9, so we have

$M=\frac{5}{9}=-\frac{s'}{s}$

which can be rewritten as

$s'=-M s = -\frac{5}{9}s$

which means that s' has opposite sign than s: therefore, the image is virtual.

F. 12.0 cm

From the magnification equation, we can write

$s'=-Ms$

and then we can substitute it into the lens equation:

$\frac{1}{f}=\frac{1}{s}+\frac{1}{s'}\\\frac{1}{f}=\frac{1}{s}+\frac{1}{-Ms}$

and we can solve for s:

$\frac{1}{f}=\frac{M-1}{Ms}\\f=\frac{Ms}{M-1}\\s=\frac{f(M-1)}{M}=\frac{(-15 cm)(\frac{5}{9}-1}{\frac{5}{9}}=12.0 cm$

G. -6.67 cm

Now the image distance can be directly found by using again the magnification equation:

$s'=-Ms=-\frac{5}{9}(12.0 cm)=-6.67 cm$

And the sign of s' (negative) also tells us that the image is virtual.

H. -24.0 cm

In this case, the image is twice as tall as the object, so the magnification is

M = 2

and the distance of the image from the lens is

s' = -24 cm

The problem is asking us for the image distance: however, this is already given by the problem,

s' = -24 cm

so, this is the answer. And the fact that its sign is negative tells us that the image is virtual.

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2 years ago

What is the momentum of a 533 kg blimp moving east at +75 m/s

mylen [45]

Answer:

39975kgm/s due east

Explanation:

Given parameters:

Mass of the blimp = 533kg

Velocity = +75m/s due east

Unknown:

Momentum of the body = ?

Solution:

The momentum of a body is the amount of motion it posses.

Momentum is the product of mass and velocity;

Momentum = mass x velocity

Insert the parameters and solve;

Momentum = 533 x 75 = 39975kgm/s

The momentum of the body is 39975kgm/s due east

7 0

1 year ago

Paano nakatulong ang estratehikong lokasyon ng Pilipinas sa paghubog ng ating kasayasayan?​

Paano nakatulong ang estratehikong lokasyon ng Pilipinas sa paghubog ng ating kasayasayan?