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Lilit [14]
2 years ago
11

An electron beam enters a crossed-field velocity selector with magnetic and electric fields of 2.0 mT and 6.0×10^3 N/C, respecti

vely. (a) What must the velocity of the electron beam be to traverse the crossed fields undeflected? If the electric field is turned off? (b) What is the acceleration of the electron beam?(c) What is the radius of the circular motion that results?
Physics
1 answer:
yaroslaw [1]2 years ago
3 0

Answer:

a)   v = 3 10⁶ m / s , b)   a = 1.055 10¹² m / s² , c)    r = 8.53 m

Explanation:

a) Let's use Newton's Second Law of Balance, so that electrons do not deviate

      F_{e} - F_{m} = 0

      F_{e} =  F_{m}

     q E = q v B

     v = E / B

Let's calculate

    v = 6.0 10³ / 2.0 10⁻³

    v = 3 10⁶ m / s

b) If the electric field is disconnected, the only force left is the magnetic one

    F_{m} = m a

    q v B = m a

    a = q / m v B

    a = q / m (E / B) B

    a = q / m E

    a = 1.6 10⁻¹⁹ /9.1 10⁻³¹ 6.0 10³

    a = 1.055 10¹² m / s²

c) Acceleration is centripetal

    a = v² / r

    r = v² / a

    r = (3 10⁶)² /1.055 10¹²

    r = 8.53 m

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Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.75 A out of the jun
AlexFokin [52]

Answer:

number of electrons = 2.18*10^18 e

Explanation:

In order to calculate the number of electrons that move trough the second wire, you take into account one of the Kirchoff's laws. All the current that goes inside the junction, has to go out the junction.

Then, if you assume that the current of the wire 1 and 3 go inside the junction, then, all this current have to go out trough the second junction:

i_1+i_3=i_2                 (1)

i1 = 0.40 A

i2 = 0.75 A

you solve the equation i3 from the equation (1):

i_3=i_2-i_1=0.75A-0.40A=0.35A

Next, you take into account that 1A = 1C/s = 6.24*10^18

Then, you have:

0.35A=0.35\frac{C}{s}=0.35*\frac{6.24*10^{18}e}{s}=2.18*10^{18}\frac{e}{s}

The number of electrons that trough the wire 3 is 2.18*10^18 e/s

3 0
2 years ago
Sunitha can type 1800 words in half an hour. What is her typing speed in words per minute?
Andre45 [30]

Answer:

60words/minute

Explanation:

If Sunitha can type 1800 words in half an hour, this can be expressed as;

1800 words = 30 minutes

To get her typing speed per minute, we will use the formula

Speed = Number of words/Time used

Typing speed = 1800/30

Typing speed = 60words/minute

Hence her typing speed in words per minute is 60words/minute

6 0
1 year ago
How much energy does a 50 kg rock have if it is sitting on the edge of a 15 m cliff?
noname [10]

Answer:

7350 J

Explanation:

The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

U=mgh

where

m is the mass of the rock

g is the gravitational acceleration

h is the height of the cliff

In this problem, we have

m = 50 kg

g = 9.8 m/s^2

h = 15 m

Substituting numbers into the formula, we find:

U=(50 kg)(9.8 m/s^2)(15 m)=7350 J

3 0
2 years ago
If 500 thousand btus of energy are available to raise the temperature of a water boiler from 20°f to 100°f, how many gallons o
sashaice [31]
In this question, you are given the energy( 500,000btus) and the temperature difference( 100F-20F= 80F). You are asked to find the volume of water.
1 BTU mean 1 degree of F increased for 1 pound mass. First, we can calculate the mass of the water in lb unit. The calculation would be:

mass= energy/temperature increase = 500,000/80= 6250lb.

Then we need to convert the weight into gallons. The calculation would be:
6250lb x kg/2.204lb x 1kg/m3 x 264.172 gallons/m3= 3638969.3 gallons
7 0
2 years ago
A ship 1200m off shore fires a gun. how long after the gun is fired will it be heard on the shore?​
ryzh [129]

Answer:

We know that the speed of sound is 343 m/s in air

we are also given the distance of the boat from the shore

From the provided data, we can easily find the time taken by the sound to reach the shore using the second equation of motion

s = ut + 1/2 at²

since the acceleration of sound is 0:

s = ut + 1/2 (0)t²

s = ut    <em>(here, u is the speed of sound , s is the distance travelled and t is the time taken)</em>

Replacing the variables in the equation with the values we know

1200 = 343 * t

t = 1200 / 343

t = 3.5 seconds (approx)

Therefore, the sound of the gun will be heard at the shore, 3.5 seconds after being fired

6 0
2 years ago
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