Steep safety ramps are built beside mountain highways to enable vehicles with defective brakes to stop safely. A truck enters a
1 answer:
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Answer:
2.08 kg
Explanation:
Newton's second law states that the acceleration of an object is proportional to the force applied to the object, according to the equation:
where F is the force applied, m is the mass of the object and a its acceleration.
In this situation, the soccer ball is kicked with a force F=13.5 N and its acceleration is a=6.5 m/s^2, therefore its mass is
Refer to the figure shown below.
m₁ = 1100 kg, the mass of the car
m₂ = 700 kg, the mass of the trailer and boat
F = 1900 N, the driving force acting on the car
N₁ = m₁g, the normal reaction on the car
N₂ = m₂g, the normal force on the trailer and boat
μN₁ and μN₂ are frictional forces, where = kinetic coefficient of friction
T = the force in the hitch between the car and trailer.
Part (a)
Let R₁ = the total force that resists the motion of the car, boat, and trailer.
Because the acceleration is 0.550m/s², therefore
(m₁ + m₂ kg)*(0.55 m/s²) = F
(1100+700 kg)*(0.55 m/s²) = (1900 - R₁) N
990 = 1900 - R
R₁ = 910 N
Answer: The resistive force is 910 N
Part (b)
80% of the resistive forces are experienced by the boat and trailer.
Let the resistive force be R₂.
Then
R₂ = 0.8*R₁ = 728 N
If the tension in the hitch between the car and the trailer is T, then
T - R₂ = m₂(0.55 m/s²)
(T - 728 N) = (700 kg)*(0.55 m/s²)
T - 728 = 385
T = 1113 N
Answer: The force in the hitch is 1113 N
m₁ = 1100 kg, the mass of the car
m₂ = 700 kg, the mass of the trailer and boat
F = 1900 N, the driving force acting on the car
N₁ = m₁g, the normal reaction on the car
N₂ = m₂g, the normal force on the trailer and boat
μN₁ and μN₂ are frictional forces, where = kinetic coefficient of friction
T = the force in the hitch between the car and trailer.
Part (a)
Let R₁ = the total force that resists the motion of the car, boat, and trailer.
Because the acceleration is 0.550m/s², therefore
(m₁ + m₂ kg)*(0.55 m/s²) = F
(1100+700 kg)*(0.55 m/s²) = (1900 - R₁) N
990 = 1900 - R
R₁ = 910 N
Answer: The resistive force is 910 N
Part (b)
80% of the resistive forces are experienced by the boat and trailer.
Let the resistive force be R₂.
Then
R₂ = 0.8*R₁ = 728 N
If the tension in the hitch between the car and the trailer is T, then
T - R₂ = m₂(0.55 m/s²)
(T - 728 N) = (700 kg)*(0.55 m/s²)
T - 728 = 385
T = 1113 N
Answer: The force in the hitch is 1113 N
The temperature of the gas is about 600 K
The Ideal Gas Law that needs to be recalled is:
<em>P = Pressure (Pa)</em>
<em>V = Volume (m³)</em>
<em>n = number of moles (moles)</em>
<em>R = Gas Constant (8.314 J/mol K)</em>
<em>T = Absolute Temperature (K)</em>
Let us now tackle the problem !
<u><em>Question (Translation):</em></u>
<em>A total of 0.2 moles of ideal gas are in containers with volume of 10 liters and a pressure of 1 atm. What is the temperature of the gas?</em>
<u>Given:</u>
number of moles = n = 0.2 moles
volume of gas = V = 10 liters
pressure of gas = P = 1 atm
gas contant = R = 0.0821 L.atm/mol.K
<u>Unknown:</u>
temperature of gas = T = ?
<u>Solution:</u>
- Minimum Coefficient of Static Friction : brainly.com/question/5884009
- The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
- Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
Grade: High School
Subject: Physics
Chapter: Pressure
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
