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2 years ago

A jet engine gets its thrust by taking in air, heating and compressing it, and

Physics

1 answer:

nadya68 [22]2 years ago

4 0

Answer:

$F=ma=20\ Kg\ 400\ m/s^2=8,000\ Nw$

Explanation:

Thrust is known as a reaction force which appears when a system expels or accelerates mass in one specific direction. If we know the acceleration and the mass of the air expelled by the jet engine, we can compute the thrust .

The acceleration is calculated by using the dynamics formula

$\displaystyle a=\frac{v_f-v_o}{t}$

The values are

$v_f=500\ m/s,\ v_o=100\ m/s,\ t=1\ sec$

$\displaystyle a=\frac{500-100}{1}=400\ m/s^2$

The thrust is

$F=ma=20\ Kg\ 400\ m/s^2=8,000\ Nw$

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Answer:

(a) Rm = 268.4 m

(b) f = 6

Explanation:

The horizontal range of a projectile is given by the following formula:

R = V₀² Sin 2θ/g

(a)

For moon:

R = Range on moon = Rm

V₀ = Launch Speed = 28 m/s

θ = Launch Angle = 17°

g = acceleration due to gravity on moon = (9.8 m/s²)/6 = 1.63 m/s²

Therefore,

Rm = (28 m/s)²Sin (2*17°)/(1.63 m/s²)

(b)

For Earth:

R = Range on Earth = Re

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θ = Launch Angle = 17°

g = acceleration due to gravity on Earth = 9.8 m/s²

Therefore,

Re = (28 m/s)²Sin (2*17°)/(9.8 m/s²)

Re = 44.7 m

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2 years ago

Anne is working on a research project that involves the use of a centrifuge. Her samples must first experience an acceleration o

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Answer:

The final rotation is 2.449 times the initial rotation

Explanation:

Centripetal acceleration and rotation speed of particle is related as

a=rω²

where ω is angular speed and r radius of circle

Rearranging equation

ω= $\sqrt{\frac{a}{r} }$

The initial acceleration is given by

a₁ =100g

The final acceleration of particle is

a₂ = 6 (100g)

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ω2= $\sqrt{\frac{600g}{100g} } *w1$

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2 years ago

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2 years ago

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You and your friend throw balloons filled with water from the roof of a several story apartment house. You simply drop a balloon

Aleks [24]

Answer:

Height = 53.361 m

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From the given information we make the following summary

$u_{1}$ = 0m/s

$t_{1}$ = t

$u_{2}$ = 43.12m/s

$t_{2}$ = (t-2.2)s

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$D = u_{1} t_{1} + \frac{1}{2} at_{1}^2$

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Inputting the values

$D = (0)t + \frac{1}{2} (9.8)t^2\\ D = 4.9t^2$

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$D = u_{2} t_{2} + \frac{1}{2} at_{2}^2$

Inputting the values

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simplifying

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Substituting D of the first balloon into the D of the second balloon and solving

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$D = 4.9(3.3)^2\\ D = 53.361 m$

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2 years ago