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aleksley [76]
2 years ago
11

A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of

the torque on the dipole when (a) the dipole is parallel to the electric field,
Physics
1 answer:
Over [174]2 years ago
8 0

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

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Onur drops a basketball from a height of 10\,\text{m}10m10, start text, m, end text on Mars, where the acceleration due to gravi
Doss [256]

Answer:

Explanation:

Given that,

Basket ball is drop from height

H=10m

It is dropped on planet mass

And the acceleration due to gravity on Mars is given as

g= 3.7m/s²

Time taken for the ball to reach the ground

Initial velocity of the body is zero

u=0m/s

Using equation of motion: free fall

H = ut + ½gt²

10 = 0•t + ½ × 3.7 ×t²

10 = 0 + 1.85t²

10 = 1.85t²

Then, t² =10/1.85

t² = 5.405

t = √ 5.405

t = 2.325seconds

So the time the ball spend on the air before reaching the ground is 2.325 seconds

5 0
2 years ago
When the wind kicks up dust and sand, the dust grains are charged. The small grains tend to get a negative charge, and the large
diamong [38]

Answer:

Explanation:

Small grains are negatively charged by the wind while big grains is positively charged and remains at the ground . This process creates an electric field due to the presence of oppositely charged particles.

When ever electric field exists it is directed from a positive charge to a negative charge so the here electric field is towards an upwards direction.                  

4 0
2 years ago
1. A liquid of mass 250g is heated with an electric heater. Its temperature rises from 30°C to 80°C, the specific heat capacity
statuscvo [17]

Answer:

1) 50 seconds 2) 100°C

Explanation:

(Follows formula of Power=Energy/Time)

1) 500W x X = 2000J/kg°C x .25kg x 50°C

X = 50 seconds.

2) 2000W x 300s = 1000J/kg°C x 2kg x X

X = 300

Initial temperature => 400°C-300°C = 100°C

8 0
2 years ago
It's your birthday, and to celebrate you're going to make your first bungee jump. You stand on a bridge 110 m above a raging riv
zzz [600]

Answer:

h=20.66m

Explanation:

First we need the speed when the cord starts stretching:

V_2^2=V_o^2-2*g*\Delta h

V_2^2=-2*10*(-31)

V_2=24.9m/s   This will be our initial speed for a balance of energy.

By conservation of energy:

m*g*h+1/2*K*(h_o-l_o-h)^2-m*g*(h_o-l_o)-1/2*m*V_2^2=0

Where

h is your height at its maximum elongation

h_o is the height of the bridge

l_o is the length of the unstretched bungee cord

800h+21*(79-h)^2-63200-24800.4=0

21h^2-2518h+43060.6=0 Solving for h:

h_1=20.66m  and h_2=99.24m  Since 99m is higher than the initial height of 79m, we discard that value.

So, the final height above water is 20.66m

6 0
2 years ago
Read 2 more answers
If the coefficient of static friction between a table and a uniform massive rope is μs, what fraction of the rope can hang over
astra-53 [7]
Let me give you the procedure like this:
Lets say that F is the fraction of the rope hanging over the table
If its like that then we have to take into account that the <span>friction force keeping on table is given by the following formula:</span>
<span>Ff = u*(1-f)*m*g </span>
and we need to know aso that <span>gravity force pulling off the table Fg is given by this other formula:</span>
<span>Fg = f*m*g </span>
What you need to do is <span>Equate the two and solve for f: </span>

<span>f*m*g = u*(1-f)*m*g </span>
<span>=> f = u*(1-f) = u - uf </span>
<span>=> f + uf = u </span>
=> f = u/(1+u) = fraction of rope
With that you can find the answer

8 0
2 years ago
Read 2 more answers
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