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aleksley [76]
2 years ago
11

A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of

the torque on the dipole when (a) the dipole is parallel to the electric field,
Physics
1 answer:
Over [174]2 years ago
8 0

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

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When photons with a wavelength of 310. nm strike a magnesium plate, the maximum velocity of the ejected electrons is 3.45 105 m/
Kisachek [45]
This problem can be solved based on the rule of energy conservation, as the energy of the photon covers both the energy needed to overcome the binding energy as well as the energy of ejection.

The rule can be written as follows:
energy of photon = binding energy + kinetic energy of ejectection
(hc) / lambda = E + 0.5 x m x v^2 where:
h is plank's constant = 6.63 x 10^-34 m^2 kg / s
c is the speed of light = 3 x 10^8 m/sec
lambda is the wavelength = 310 nm
E is the required binding energy
m is the mass of photon = 9.11 x 10^-31 kg
v is the velocity = 3.45 x 10^5 m/s

So, as you can see, all the parameters in the equation are given except for E. Substitute to get the required E as follows:
(6.63x10^-34x3x10^8)/(310x10^-9) = E + 0.5(9.11 x 10^-31)(3.45x10^5)^2
E = 6.41 x 10^-16 joule

To get the E in ev, just divide the value in joules by 1.6 x 10^-19
E = 4.009 ev
3 0
2 years ago
Essam is abseiling down a steep cliff. How much gravitational potential energy does he lose for every metre he descends? His mas
Dafna11 [192]

Answer:

720 J

Explanation:

The gravitational potential energy that Essam loses for every metre is given by:

\Delta U=mg \Delta h

where

m=72 kg is Essam's mass

g=10 N/kg is the gravitational field strength

\Delta h=1 m is the difference in height

By substituting the numbers into the formula, we find

\Delta U=(72 kg)(10 N/kg)(1 m)=720 J

5 0
2 years ago
Read 2 more answers
The speed of sound in air is 320 ms-1 and in water it is 1600 ms-1. It takes 2.5 s for sound to reach a certain distance from th
Nonamiya [84]

Answer:

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

Explanation:

Given:

Speed of sound in air = 320 m/s

Speed of sound in water = 1600 m/s

Time taken to reach certain distance in air = 2.5 sec

a.

We have to find the distance traveled by sound in air.

Distance = Product of speed and time.

⇒ Distance = Speed\times time\ taken

⇒ Distance = 320\times 2.5

⇒ Distance = 800 meters.

b.

Now we have to find how much time the sound will take to travel in water.

⇒ Time = Ratio of distance and speed

⇒ Time =\frac{distance}{speed}

⇒ Time =\frac{800}{1600}   <em>   ...distance = 800 m and speed = 1600 m/s</em>

⇒ Time =\frac{1}{2}

⇒ Time =0.5 seconds.

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

7 0
2 years ago
A skydiver finds that she speeds up when she holds her arms close to her body. What does this do?
ArbitrLikvidat [17]

D. Reduces the force of air resistance

7 0
2 years ago
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A container of nitrogen (an ideal diatomic gas, molecular weight=28) is at a pressure of 2 atm and has a mass density of 1.6 gra
Nikolay [14]

Answer:

Explanation:What is the root-mean-square velocity (vrms) of the center of mass of one of the molecules?

3 0
2 years ago
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