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Vedmedyk [2.9K]
2 years ago
8

Which sequence correctly shows how stars form?

Physics
2 answers:
vampirchik [111]2 years ago
8 0

Answer:

The correct answer is B

Explanation:

Romashka-Z-Leto [24]2 years ago
7 0
The correct answer is <span>nebula forms → nebula collapses → protostar forms → fusion begins</span>
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One nucleus contains 31 protons and 40 neutrons another nucleus contains 31 protons and 41 neutrons what can you conclude about
Pavel [41]

They are isotopes of the same element.

5 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST AND 100 POINTS! NEED THIS ASAP!
lorasvet [3.4K]

Answer:

6.57, 1.64, .88

Explanation:

all correct on edge

8 0
1 year ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
Greeley [361]

Answer:

I = 215.76 A  

Explanation:

The direction of magnetic field produced by conductor 1 on the location of conductor 2 is towards left. Based on Right Hand Rule -1 and taking figure 21.3 as reference, the direction of force Fm due to magnetic field produced at C_2 is shown above. The force Fm balances the weight of conductor 2.  

Fm = u_o*I^2*L/2*π*d

where I is the current in each rod, d = 0.0082 m is the distance 27rId  

between each, L = 0.85 m is the length of each rod.

Fm = 4π*10^-7*I^2*1.1/2*π*0.0083

The mass of each rod is m = 0.0276 kg  

F_m = mg

4π*10^-7*I^2*1.1/2*π*0.0083=0.0276*9.8

I = 215.76 A  

note:

mathematical calculation maybe wrong or having little bit error but the method is perfectly fine

5 0
2 years ago
A child on a playground swing is swinging back and forth (one complete oscillation) once every four seconds, as seen by her fath
Sati [7]

Answer:

A

Explanation:

Solution:-

- According to the law of relativity the relative speed between two moving objects is inversely proportional to the the time taken.

- Ignoring Doppler Effect.

- So if the relative speeds of two objects in motion i.e ( swing and spaceship) are positive then the time frame of reference for both object relative to other other decreases. So in other words if spaceship approaches the swing i.e relative velocity is positive then the time period of oscillation observed would be less than actual i.e less than 4 seconds.

- Similarly, if spaceship moves away from the swing i.e relative velocity is negative then the time period of oscillation observed would be more than actual i.e more than 4 seconds.

4 0
1 year ago
In conventional television, signals are broadcast from towers to home receivers. Even when a receiver is not in direct view of a
fgiga [73]

(a) The diffraction decreases

The formula for the diffraction pattern from a single slit is given by:

sin \theta = \frac{n \lambda}{a}

where

\theta is the angle corresponding to nth-minimum in the diffraction pattern, measured from the centre of the pattern

n is the order of the minimum

\lambda is the wavelength

a is the width of the opening

As we see from the formula, the longer the wavelength, the larger the diffraction pattern (because \theta increases). In this problem, since the wavelength of the signal has been decreased from 54 cm to 13 mm, the diffraction of the signal has decreased.

(b) 10.8^{\circ}

The angular spread of the central diffraction maximum is equal to twice the distance between the centre of the pattern and the first minimum, with n=1. Therefore:

sin \theta = \frac{(1) \lambda}{a}

in this case we have

\lambda=54 cm = 0.54 m is the wavelength

a=5.7 m is the width of the opening

Solving the equation, we find

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.54 m}{5.7 m})=5.4^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 5.4^{\circ}=10.8^{\circ}

(c) 0.26^{\circ}

Here we can apply the same formula used before, but this time the wavelength of the signal is

\lambda=13 mm=0.013 m

so the angle corresponding to the first minimum is

\theta = sin^{-1} (\frac{\lambda}{a})=sin^{-1} (\frac{0.013 m}{5.7 m})=0.13^{\circ}

So the angular spread of the central diffraction maximum is twice this angle:

\theta = 2 \cdot 0.13^{\circ}=0.26^{\circ}

5 0
2 years ago
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