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Goshia [24]
2 years ago
15

A point charge Q = -400 nC and two unknown point charges, q1 and q2, are placed as shown. Point charge q1 is located 1.3 meters

along the +x-axis, point charge q2 is located 0.7 meters down the -y-axis, and point charge Q is located 2.0 meters from the origin at an angle of 30° above the x-axis. At the origin, the three charges together create an electric field that has magnitude zero. What is the charge q1?
150 nC

120 nC

–120 nC

–150 nC

250 nC
Physics
1 answer:
nalin [4]2 years ago
6 0
120 nC is the answer




Sorry if I’m wrong
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An ambulance moving at 42 m/s sounds its siren whose frequency is 450 hz. a car is moving in the same direction as the ambulance
Korvikt [17]
(a) Since the ambulance and the car are moving one relative to each other, we have to use the general formula of the Doppler effect, which gives us the shift of the frequency of the siren as heard by an observer in the car:
f'=( \frac{v+v_o}{v+v_s} )f
where
f' is the apparent frequency as heard by the observer in the car
v is the velocity of the wave 
v_o is the velocity of the observer (positive if it is moving towards the source, negative if it is moving away)
v_s is the velocity of the source (positive if the source is moving away from the observer, negative if is is moving towards it)
f is the real frequency of the sound

In the first part of the problem:
v=343 m/s (speed of the sound wave)
v_o =-25 m/s (the car is moving away from the ambulance)
v_s = -42 m/s (the ambulance is moving towards the car)
f=450 Hz (original frequency of the sound)

If we plug the numbers into the formula, we find
f'=( \frac{343 m/s-25 m/s}{343 m/s-42 m/s} )(450 Hz)=475 Hz

b) This time, the ambulance passes the car, so the ambulance is now moving away from the car; this means that v_s must be positive:
v_s=+42 m/s
Moreover, the car is now moving towards the ambulance, so we should reverse also the sign of v_o:
v_o=+25 m/s
All the other data do not change, so if we use the same formula as before, we find
f'=( \frac{343 m/s+25 m/s}{343 m/s+42 m/s} )(450 Hz)=430 Hz
8 0
2 years ago
Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te
QveST [7]

Answer:

Please see attachment

Explanation:

Please see attachment

8 0
2 years ago
A plane initially traveling at 200 m/s due west experiences a 10 m/s head wind coming from the opposite direction. A). What will
Hitman42 [59]
Ok so it would be late and the relative velocity would be 190 m/s because 200 m/s - 10 m/s is 190 m/s. Hope this helps.
8 0
2 years ago
Which of the following best describes an action-reaction pair? A. The Moon Pulls on Earth, and Earth pulls back on the moon. B.
Papessa [141]
An action-reaction pair would be a pair in which one of the elements exerts a force on the other element (action), and then the other element would respond to this force by exerting another force in the opposite direction (reaction).

From the given choices, we will see that:
For choice A, the moon exerts a force on the earth by pulling it (action) and the earth responds to this force by pulling the moon (reaction in opposite direction of the action).

Therefore, the correct choice would be: 
A. <span>The Moon Pulls on Earth, and Earth pulls back on the moon.</span>
4 0
2 years ago
Read 2 more answers
A 69.0 kg ice skater moving to the right with a velocity of 2.61 m/s throws a 0.22 kg snowball to the right with a velocity of 2
Luda [366]

Answer:

0.08m/s

Explanation:

Given data

M1= 69kg

v1= 2.61m/s

M2= 0.22kg

v2= 25.2m/s

Before snowball is thrown:

Total mass of skater + snowball = 69+ 0.22 = 69.22kg

Total Momentum of skater + snowball = mv = 69.22 x 2.61 = 180.7 kgm/s

After snowball is thrown:

Let's call the velocity of the skater V.

Total momentum = momentum of skater + momentum of snowball

=69.22V + (5.544)

= 69.22V + 5.544

So:

180.7  = 69.22V+5.544

180.7- 5.544= 69.22V

175.156= 69.22V

V= 175.156/69.22

V = 2.53m/s

The total momentum after catching the snowball is mV or:

(69.0 + 0.22) x V

So:

5.544= 69.22V

V= 5.544/69.22

V=0.08m/s

The velocity of the ice skater after throwing the snowball is 0.08m/s

4 0
1 year ago
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