Answer:
d. less than 20m/s
Explanation:
To the 2nd car, the first car is travelling 10m/s east and 10m/s south. So the total velocity of the first car with respect to the 2nd car is
[tex]\sqrt{10^2 + 10^2} =10\sqrt{2}=14.14m/s
As 14.14m/s is less than 20m/s. d is the correct selection for this question.
Answer:
The answer is 3.
Explanation:
The answer to this question can be found by applying the right hand rule for which the pointer finger is in the direction of the electron movement, the thumb is pointing in the direction of the magnetic field, so the effect that this will have on the electrons is the direction that the middle finger points in which is right in this example.
So as a result of the magnetic field directed vertically downwards which is at a right angle with the electron beams, the electrons will move to the right and the spot will be deflected to the right of the screen when looking from the electron source.
I hope this answer helps.
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,
E = mgh
where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,
E = m(9.8 m/s²)(0.5 m) = 4.9m
Hence, the potential energy is equal to 4.9m.
Answer:
Acceleration, 
Explanation:
Given that,
The dogs of four-time Iditarod Trail Sled Dog Race champion Jeff King pull two 100-kg sleds that are connected by a rope, m = 100 kg
Force exerted by the doges on the rope attached to the front sled, F = 240 N
To find,
The acceleration of the sleds.
Solution,
Let a is the acceleration of the sleds. The product of mass and acceleration is called force. Its expression is given by :
F = ma

(m = 2m)

So, the acceleration of the sleds is
.
Answer:
Angular displacement of the turbine is 234.62 radian
Explanation:
initial angular speed of the turbine is



similarly final angular speed is given as



angular acceleration of the turbine is given as

now we have to find the angular displacement is given as


