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Savatey [412]
2 years ago
14

The strength of the gravitational field of a source mass can be measured by the magnitude of the acceleration due to gravity at

a field point. Thus the gravitational field strength at a point depends on the distance from the source mass. For this problem assume that Earth’s mass is concentrated at its center and that Earth has a radius of RE = 6,378 km at sea level and a mass of ME = 5.972×1024 kg. Ignore any forces due to Earth’s rotation or due to other astronomical bodies.
Physics
1 answer:
Svetradugi [14.3K]2 years ago
5 0

Answer:

9.79211 m/s²

Explanation:

M = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6378000 m

g=G\frac{M}{r^2}\\\Rightarrow g=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6378000)^2}\\\Rightarrow g=9.79211\ m/s^2

The acceleration due to gravity is 9.79211 m/s²

For any distance above the Earth's surface h

g=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6378000+h)^2}\\\Rightarrow g=\frac{3.983324\times 10^{14}}{6378000+h}\ m/s^2

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Answer:

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Explanation:

The inertia can be find using

a.

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m = 0.95 g * \frac{1 kg}{1000g}=9.5x10^{-4} kg

r=0.54 cm * \frac{1m}{100cm} =5.4x10^{-3}m

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I=2.77x10^{-8} kg*m^2

now to find the torsion constant can use knowing the period of the balance

b.

T=0.5 s

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2 years ago
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