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steposvetlana [31]
2 years ago
7

Carl and Abby are discussing what they have learned in class about electricity and magnetism. Carl tells Abby that an electric c

urrent running along a wire can be used to produce a magnetic force. Abby, on the other hand, tells Carl that moving electrons through a magnetic field can produce an electric current.
Which of the students is/are correct?

Both Carl and Abby are correct.

Only Carl is correct.

Only Abby is correct.

Neither student is correct.
Physics
1 answer:
Vikki [24]2 years ago
8 0
Both? I'm not too sure
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The two major problems with most motor vehicles are that they burn fossil fuels and _____________.
Citrus2011 [14]

Answer:

A. Create radioactive waste i believe

Explanation:

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2 years ago
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Jade and her roommate Jari commute to work each morning, traveling west on I-10. One morning Jade left for work at 6:45 A.M., bu
Veronika [31]

Answer:

Jari

Explanation:

The question requires to know who is traveling faster. This is done by comparing the gradients. The steeper the slope (high gradient), the faster the speed and vice versa.

From Jari's line, the starting point is (0, 0) and another point is (6, 7)

The gradient being change in y to change in x

Change in y=7-0=7

Change in x=6-0=6

Slope is 7/6

For Jade, first point is (0, 10) then another point is (6, 16)

Change in y=16-10=6

Change in x=6-0=6

Slope is 6/6=1

Clearly, 7/6 is greater than 6/6 or 1 hence Jari is faster than Jade

3 0
2 years ago
Ingrid is moving a box from the ground into the back of a truck. She uses 20 N of force to move the box 5 meters. If she uses an
Oduvanchick [21]

Answer:

C

Explanation:

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2 years ago
A constant torque of 200Nm turns a wheel about its centre. The moment of inertia of it about the axis is 100kgm^s . Find the kin
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It would turn  160 degrees after twenty truns

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2 years ago
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First find ∮RB⃗ ⋅dl⃗ , the line integral of B⃗ around a loop of radius R located just outside the left capacitor plate. This can
Allisa [31]

Answer:

the expression of current in the loop enclosed to the left of the capacitor plate is

I(t) = \frac{1}{\mu_0}\int B. dL

Explanation:

As we know by Ampere's law that line integral of magnetic field around a closed loop is proportional to the current enclosed in the path

So we will have

\int B. dL = \mu_0 I(t)

so we have

I(t) = \frac{1}{\mu_0}\int B. dL

so above is the expression of current in the loop enclosed to the left of the capacitor plate

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2 years ago
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