Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration, 
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,
Frictional force is given by :
F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.
They would be likely to be underweight. This is because the role of villi is to increase absorption of soluble molecules, they do this by increasing surface area for absorption to occur across.
If the person has less villi than normal in their small intestine, then the surface area will not be as large meaning there is less area for absorption to occur across so less soluble molecules will be absorbed.
I really wish I could be helping you. I don't know.
Answer:
So Tammy must move with speed 4.76 m/s in opposite direction of Jackson
Explanation:
As per law of conservation of momentum we know that there is no external force on it
So here we can say that initial momentum of the system must be equal to the final momentum of the system
now we have
final they both comes to rest so here we can say that final momentum must be zero
now we have
Answer:
v = 69.82 ms^-1
Explanation:
As we know,
R = vi2 sin2Ꝋ / g
vi2 =R g / sin2 Ꝋ where R is range R = 52m, Ꝋ = 3 Degrees
vi2 = 52 x 9.8 / sin 2(3) = 4875.227
v = 69.82 ms^-1
