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jenyasd209 [6]
2 years ago
5

A liquid in a test tube has a curved surface such that the edges touching the glass are higher than the surface at the center. T

his must mean that the cohesive forces are less than the adhesive forces. 1. False 2. True

Physics
1 answer:
stepladder [879]2 years ago
4 0

Answer:

True

Explanation:

Cohesive forces are forces that exist between  the molecules of a substance of the same material while adhesive forces are forces that exists between the molecules of the substances of different materials.

This is responsible for the  nature of menisci formed by different liquids when they are filled into containers or glass tubes.

If the cohesive forces of the liquid molecules are stronger than the adhesive forces between the liquid molecules and the glass material, a convex meniscus will be formed. This means that the edges of the liquid touching the glasses are lower than the surface at the centre. The meniscus formed by mercury in a glass tube is an example of this.

However, If the cohesive forces of the liquid molecules are weaker than the adhesive forces between the liquid molecules and the glass material, a concave meniscus will be formed. This means that the edges of the liquid touching the glasses are higher than the surface at the centre. The meniscus formed by water in a glass tube is an example of this.

Please view the attached diagram:

Please note: I got the diagram online, it was not drawn by me. I Just needed to quickly get something to illustrate my explanations. Thanks.

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Answer:

The centripetal force acting on the child is 39400.56 N.

Explanation:

Given:

Mass of the child is, m=40\ kg

Radius of the barrel is, R=2.90\ m

Number of revolutions are, n =10

Time taken for 10 revolutions is, t=29.3\ s

Therefore, the time period of the child is given as:

T=\frac{n}{t}=\frac{10}{29.3}=0.341\ s

Now, angular velocity is related to time period as:

\omega=\frac{2\pi}{T}=\frac{2\pi}{0.341}=18.43\ rad/s

Now, centripetal force acting on the child is given as:

F_{c}=m\omega^2 R\\F_{c}=40\times (18.43)^2\times 2.90\\F_{c}=40\times 339.66\times 2.90\\F_{c}=39400.56\ N

Therefore, the centripetal force acting on the child is 39400.56 N.

8 0
2 years ago
Use Newton's laws of motion to explain why it is important that baseballs and softballs each have a small acceptable range of ma
tiny-mole [99]

Explanation:

new non law neutron means neutral then it's important that baseball and softball features small respectable range of masses soft it means that when a ball hits anything hard it comes back by the Newton Law if the baseball is big and the small boy small and then if the contract with each other they ignore triple so when a ball hits the wall if the comeback because of the Mutants and when a big ball if we throw it to the wall it doesn't come that it comes back but in a very low way because it contains less neutrons in it if it is helpful please share with me

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2 years ago
As an object in motion becomes heavier, its kinetic energy _____. A. increases exponentially B. decreases exponentially C. incre
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Jim stands beside a wide river and wonders how wide it is. he spots a large rock on the bank directly across from him. he then w
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To solve this problem, we must imagine that Jim’s initial position, the position of the rock, and Jim’s final position all connects to form a triangle. Now we can imagine that the triangle is a right triangle with the 90° angle on the initial position.

The angle of 30° is directly opposite to the length of his total stride while the width of the river is the side adjacent to the angle. Therefore can use the tan function to solve for the width of the river:

tan θ = opposite side / adjacent side

tan 30 = total stride distance / width of river

where total stride distance = 65 * 0.8 = 52 m

width of river = 52 m / tan 30

<span>width of river = 90.07 m</span>

7 0
2 years ago
for a given initial projectile speed, you observe that the projectile has a certain range R at a launch angle of a = 30. For wha
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Answer:

The other angle is 30 degrees.

Explanation:

The range of projectile is given by :

R=\dfrac{u^2\ \sin2\theta}{g}

Here,

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Here, \theta=30^{\circ}

We need to find the other launch angle when the projectile have the same range, such that,

\dfrac{u^2\ \sin(60)}{g}=\dfrac{u^2\ \sin2\alpha}{g}

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\alpha =30^{\circ}

So, the other angle is 30 degrees. Hence, this is the required solution.

3 0
2 years ago
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