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Hunter-Best [27]
2 years ago
10

Use Newton's laws of motion to explain why it is important that baseballs and softballs each have a small acceptable range of ma

sses.​
Physics
1 answer:
tiny-mole [99]2 years ago
5 0

Explanation:

new non law neutron means neutral then it's important that baseball and softball features small respectable range of masses soft it means that when a ball hits anything hard it comes back by the Newton Law if the baseball is big and the small boy small and then if the contract with each other they ignore triple so when a ball hits the wall if the comeback because of the Mutants and when a big ball if we throw it to the wall it doesn't come that it comes back but in a very low way because it contains less neutrons in it if it is helpful please share with me

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On a hypothetical scale X The ice point is 40° and steam point is 120°.
arlik [135]

Answer:

The reading of Y is -10°.

Explanation:

For scale X, the ice point is 40° and steam point is 120°.

Difference between the two extremes for scales X = 120 - 40 = 80

For scale X, the ice point and steam points are -30° and 130° respectively.

Difference between the two extremes for scales X = 130 - (-30) = 160

Comparing both scales:

One unit of scale X = x

One unit of scale Y = y

Scale X has 80 divisions while scale Y has 160

80x = 160y

x = 2y

50° in scale X = 10x + ice point in X scale

10 divisions in Y scale = 20y

Reading of Y scale = ice point of Y + 20y

= -30° + 20°

= -10°

7 0
2 years ago
An object is located 13.5 cm in front of a convex mirror, the image being 7.05 cm behind the mirror. A second object, twice as t
goldfiish [28.3K]

Answer:

Second object is located at 42.03 cm in front of mirror

Explanation:

In this question we have given,

object distance from convex mirror ,u=-13.5cm

Image distance from convex mirror,v=7.05cm

let focal length of convex mirror be f

we have to find the distance of second object from convex mirror

we know that u, v and f are related by following formula

\frac{1}{f} =\frac{1}{v}+ \frac{1}{u}.............(1)

put values of u and v in equation (1)

we got,

\frac{1}{f} =\frac{1}{7.05}+ \frac{1}{-13.5}

\frac{1}{f}=\frac{13.5-7.05}{13.5\times 7.05}

\frac{1}{f}=\frac{6.45}{13.5\times 7.05}\\f=13.5\times 1.09\\f=14.75

we have given that

second object is twice as tall as the first object

and image height of both objects are same

it means

o_{2}=2o_{1}\\i_{1}=i_{2}.............(2)

we know that

\frac{v}{u}=\frac{i}{o}\\i=\frac{o\times v}{u}

therefore,

i_{1}=\frac{o_{1}\times v}{u}.................(3)

put values of v and u in equation 3

i_{1}=-\frac{o_{1}\times 7.05}{13.5}

i_{1}=-0.52o_{1}

therefore from equation 2

i_{2}=-0.52o_{1}

we know that

i_{2}=\frac{o_{2}\times V}{U}.................(4)

put value of i_{2} and o_{2} in equation 4

-.52o_{1}=\frac{2o_{1}\times V}{U}

U=\frac{2o_{1}\times V}{-.52o_{1}} \\U=-3.85V

we know that U,V and f are related by following formula

\frac{1}{f} =\frac{1}{V}+ \frac{1}{U}.............(5)

put values of f and U in equation 5

we got

\frac{1}{14.75} =\frac{1}{V}- \frac{1}{3.85V}

\frac{1}{14.75} =\frac{2.85}{3.85V}

\frac{1}{14.75} =\frac{2.85}{3.85V}\\V=\frac{2.85\times 14.75}{3.85}\\V=10.91 cm

Therefore,

U=-10.91\times 3.85

U=-42.03 cm

Second object is located at 42.03 cm in front of mirror

4 0
2 years ago
A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. if the water pressure is reduced by 50%, what i
lina2011 [118]
The area of the sprinkles can be determined through the area of a circle that is pi * r^2 in which the given dimensions above are the radii, r. The second scenarios radius is only half of the original, that is 4 ft. In this case, we can compute the area of the second again. We calculate next the difference of two areas of circles. 
7 0
2 years ago
A magnetic field of 0.080 T is in the y-direction. The velocity of wire segment S has a magnitude of 78 m/s and components of 18
Annette [7]

Answer:

Part a)

Induced EMF when length vector is along Z direction is 0.72 V

Part b)

Induced EMF when length vector is along Y direction is ZERO

Explanation:

As we know that the motional EMF induced in the wire is given as

E = (v\times B). L

1)

As we know that

v = 18\hat i + 24\hat j + 72\hat k

B = 0.080 \hat j

L = 0.50 \hat k

now we have

\vec v \times \vec B = 1.44\hat k - 5.76 \hat i

so we have

E = 1.44 (0.50) = 0.72 V

2)

If the length vector is along Y direction then we have

L = 0.50 \hat j

so again we have

\vec v \times \vec B = 1.44\hat k - 5.76 \hat i

so we have

EMF = 0

6 0
2 years ago
Charge q1 is distance r from a positive point charge q. charge q2=q1/3 is distance 2r from q. what is the ratio u1/u2 of their p
makvit [3.9K]
We need the power law for the change in potential energy (due to the Coulomb force) in bringing a charge q from infinity to distance r from charge Q. We are only interested in the ratio U₁/U₂, so I'm not going to bother with constants (like the permittivity of space). 

<span>The potential energy of charge q is proportional to </span>
<span>∫[s=r to ∞] qQs⁻²ds = -qQs⁻¹|[s=r to ∞] = qQr⁻¹, </span>

<span>so if r₂ = 3r₁ and q₂ = q₁/4, then </span>
<span>U₁/U₂ = q₁Qr₂/(r₁q₂Q) = (q₁/q₂)(r₂/r₁) </span>
<span>= 4•3 = 12.</span>
5 0
2 years ago
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