<em>If the distance between the two objects is the same, then;</em>
Both the magnet and the coil moving toward each other at 10 cm/s each
A reversed polarity magnet moving away from the coil at 20 cm/s
<u>Calculate current that produces a magnetic field, and use the right hand rule 2, to determine the direction of current or the direction of magnetic field loops. </u>
Answer:
Canyon is 50.176 meter deep.
Explanation:
The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.
Given data:
Time = t = 3.2 s
Initial velocity = 
= 0 m/s
Gravitational acceleration = g = 9.8 m/s²
Height = h = ?
According to second equation of motion
As initial velocity is zero, So the first term of right hand side of above equation equal to zero
h = (0.5)(9.8)(3.2)²
h = 50.176 m
This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.
Answer:
4.9 cm
Explanation:
From Hook's Law,
F = ke......................... Equation 1
Where F= force, e = extension, k = spring constant.
Note: the Force acting on the the spring is the weight of the mass.
W = mg.
F = mg.................... Equation 2
Where m = mass, g = acceleration due to gravity
Substitute equation 2 into equation 1
mg = ke
make e the subject of the equation
e = mg/k............... Equation 3.
Given: m = 2 kg, g = 9.8 m/s², k = 400 N/m
e = (2×9.8)/400
e = 19.6/400
e = 0.049 m
e = 4.9 cm
Answer:
B i think is the answer
Explanation:
i feel like it is B because if you put them together and the answer is 1.5 so it is B
Answer:
Explanation:
Given that,
A light bulb has a resistance of 2.9ohms
R = 2.9 ohms
And a battery of 1.5V is applied
V = 1.5 V
We want to find the rate of energy transformed
First we need to know what rate of energy is
Rate of energy implies that we want to find power. Power is the rate at which work is done
P = Workdone / time
Then,
In electronic, the power dissipated by a resistor is given as
P = V² / R
P = 1.5² / 2.9
P = 0.7759 W
P ≈ 0.776 W
So, the rate at which electrical energy transformed in the lightbulb is 0.776 Watts
