Say the initial point is (0,0)
The final point is
x = 200 + 135*cos(30) = 200 + 135*sqrt(3)/2 = 316.91 ft
y = 135*sin(30) = 135/2 = 67.5 ft
Resultant vector = (316.91, 67.5) - (0,0) = 316.91, 67.5) ft
Answer:8.3m/sec 30 sec,
Explanation:
A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.
The solution would be like this for this specific problem:
F = (G Me Mo) / Re^2
F / Mo = (G Me) / Re^2
G = gravitational constant
= 6.67384 * 10^-11 m3 kg-1 s-2
Me = 5.972 * 10^24 kg
Re^2 = (6.38 * 10^6)^2 m^2
= 40.7044 * 10^12 m^2 = 4.07044 * 10^13 m^2
G Me / Re^2 = (6.67384 * 10-11
* 5.972 * 10^24) / 4.0704 * 10^13 = 9.7196 m/s^2
9.7196 m/s^2 = acceleration
due to Earth’s gravity
Therefore, the value of the composite constant (Gme / r^2e) that is to be
multiplied by the mass of the object mo in the equation above is 9.7196
m/s^2.
T = √(h)/(0.5)(9.81)
t = √(25)/(4.905)
t = √5.1
t = 2.26 seconds
hope this helps and have a great day :)
