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Elan Coil [88]
2 years ago
11

Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is yo

ur friend correct? Why or why not?
Physics
1 answer:
nalin [4]2 years ago
3 0

Answer:

Ok, let's suppose the simplest of the physical changes:

We have an object that is not moving (so it is not accelerated)

and there is change, now the object moves.

Because there was a change, means that there was an acceleration, and by the second Newton's law.

Force equals mass times acceleration:

F = m*a

There must be a force.

So suppose that you pushed the object, then some energy that you had, you transferred it to the object, that now is moving and now has kinetic energy.

Now, is kinda true that in a closed system the total energy is always constant, but it depends on what is our system.

So if we think in our system as you and the object, then in the whole system the energy does not change because the energy that you lost is now on the object, but again, there was a transfer of energy.

So no, your friend is not correct.

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A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
jasenka [17]
Answer: 70.5 km/h

Justification:

The question is not clearly stated but it seems you are asking for the x - component of the velocity of the helicopter.

You can find the x and y - components of the velocity using the trigonometric ratios sine and cosine.

The sine ratio relates the y-component and the velocity by:

sin(angle) = y-component of velocity / velocity

The cosine ratio related the x-component and the velocity by:

cos(angle) = x-component of velocity / velocity.

Since you have the angle and the velocity and are asked by the x-component of the velocity, you need to use the cosine ratio:

cos(35°)= x-component / 86.0 km/h

 => x -component = 86.0 km/h * cos(35°) = 70.5 km/h
6 0
2 years ago
Read 2 more answers
A metal sphere of radius 2.0 cm carries an excess charge of 3.0 μC. What is the electric field 6.0 cm from the center of the sph
Nonamiya [84]

Answer:

The electric field is  E = 7.5 *10^{6} \ N/C

Explanation:

From the question we are told that

    The radius of the metal sphere is  R = 2.0 \ cm  =  0.02 \ m

     The excess charge which the metal sphere carries is  q =  3.0 \mu C  =  3.0*10^{-6} \ C

      The distance of the position being to the center is D = 6.0 \ cm  = 0.06 \ m

       The coulomb constant is   k =9*10^{9} \  N \cdot m^2 /C^2

Generally the electric field is mathematically represented as  

        E = \frac{k *  q}{D^2}

substituting values

        E = \frac{9*10^{9} *  30.*10^{-6}}{(0.06)^2}

      E = 7.5 *10^{6} \ N/C

5 0
1 year ago
A coil of 1000 turns of wire has a radius of 12 cm and carries a counterclockwise current of 15A. If it is lying flat on the gro
grin007 [14]

Answer:

torque is 1.7 * 10^{-2} Nm

Explanation:

Given data

turns n = 1000 turns

radius r  = 12 cm

current I = 15A

magnitude B = 5.8 x 10^-5 T

angle θ = 25°

to find out

the torque on the loop

solution

we know that torque on the loop is

torque = N* I* A*B* sinθ

here area A = πr² = π(0.12)²

put all value

torque = N* I* A*B* sinθ

torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25

torque = 0.0166 N m

torque is 1.7 * 10^{-2} Nm

5 0
2 years ago
When were Earth’s landmasses first recognizable as the continents we know today? 10 million years ago 135 million years ago 180
Bess [88]

Answer:

b

Explanation:

i took the test

6 0
1 year ago
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As a car drives with its tires rolling freely without any slippage, the type of friction acting between the tires and the road i
Kitty [74]

Answer:

<em>B</em><em>.</em><em> </em><em>Kinetic</em><em> </em><em>friction</em><em> </em>

Explanation:

This is definitely the correct answer because kinetic friction acts when an object is in motion and it allows the object to move without slipping, etc

<em>ALSO</em><em>,</em><em> </em><em>PLEASE DO</em><em> </em><em>MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>

<em>Bonne</em><em> </em><em>journée</em><em> </em><em>;</em><em>)</em><em> </em>

6 0
2 years ago
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