answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alja [10]
2 years ago
12

A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare

st tenth. km/h
Physics
2 answers:
jasenka [17]2 years ago
6 0
Answer: 70.5 km/h

Justification:

The question is not clearly stated but it seems you are asking for the x - component of the velocity of the helicopter.

You can find the x and y - components of the velocity using the trigonometric ratios sine and cosine.

The sine ratio relates the y-component and the velocity by:

sin(angle) = y-component of velocity / velocity

The cosine ratio related the x-component and the velocity by:

cos(angle) = x-component of velocity / velocity.

Since you have the angle and the velocity and are asked by the x-component of the velocity, you need to use the cosine ratio:

cos(35°)= x-component / 86.0 km/h

 => x -component = 86.0 km/h * cos(35°) = 70.5 km/h
hichkok12 [17]2 years ago
6 0

Yeah it is 70.4 for the Ax one and 49.3 for the Ay.

You might be interested in
A migrating robin flies due north with a speed of 12 m/s relative to the air. The air moves due east with a speed of 6.8 m/s rel
Svetach [21]

I'm assuming the question is what is the robin's speed relative to to the ground...

Create an equation that describes its relative motion.

rVg = rVa + aVg


Substitute values.

rVg = 12 m/s [N] + 6.8 m/s [E]


Use vector addition.

| rVg | = √ | rVa |² + | aVg |²

| rVg | = √ 144 m²/s² + 46.24 m²/s²

| rVg | = √ 19<u>0</u>.24 m²/s²

| rVg | = 1<u>3</u>.78 m/s


Find direction.

tanФ = aVg / rVa

tanФ = 6.8 m/s / 12 m/s

Ф = 29°


Therefore, the velocity of the robin relative to the ground is 14 m/s [N29°E]

4 0
2 years ago
Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula.
sveta [45]

Answer:

the two ice skater have the same momentum but the are in different directions.

Paula will have a greater speed than Ricardo after the push-off.

Explanation:

Given that:

Two ice skaters, Paula and Ricardo, initially at rest, push off from each other. Ricardo weighs more than Paula.

A. Which skater, if either, has the greater momentum after the push-off? Explain.

The law of conservation of can be applied here in order to determine the skater that possess a greater momentum after the push -off

The law of conservation of momentum states that the total momentum of two  or more objects acting upon one another will not change, provided there are no external forces acting on them.

So if two objects in motion collide, their total momentum before the collision will be the same as the total momentum after the collision.

Momentum is the product of mass and velocity.

SO, from the information given:

Let represent the mass of Paula with m_{Pa} and its initial velocity with u_{Pa}

Let represent the mass of Ricardo with m_{Ri} and its initial velocity with u_{Ri}

At rest ;

their velocities will be zero, i.e

u_{Pa} = u_{Ri} = 0

The initial momentum for this process can be represented as :

m_{Pa}u_{Pa} +  m_{Ri}u_{Ri} = 0

after push off from each other then their final velocity will be v_{Pa} and v_{Ri}

The we can say their final momentum is:

m_{Pa}v_{Pa} +   m_{Ri}v_{Ri} = 0

Using the law of conservation of momentum as states earlier.

Initial momentum = final momentum = 0

m_{Pa}u_{Pa} +  m_{Ri}u_{Ri} =  m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}

Since the initial velocities are stating at rest then ; u = 0

m_{Pa}(0) + m_{Pa}(0) = m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}

m_{Pa}v_{Pa} +   m_{Ri}v_{Ri}  = 0

m_{Pa}v_{Pa} = - m_{Ri}v_{Ri}

Hence, we can conclude that the two ice skater have the same momentum but the are in different directions.

 B. Which skater, if either, has the greater speed after the push-off? Explain.

Given that Ricardo weighs more than Paula

So m_{Ri} > m_{Pa} ;

Then \mathsf{\dfrac{{m_{Ri}}}{m_{Pa} }= 1}

The magnitude of their momentum which is a product of mass and velocity can now be expressed as:

m_{Pa}v_{Pa} =  m_{Ri}v_{Ri}

The ratio is

\dfrac{v_{Pa}}{v_{Ri}} =\dfrac{m_{Ri}}{m_{Pa}} = 1

v_{Pa} >v_{Ri}

Therefore, Paula will have a greater speed than Ricardo after the push-off.

6 0
2 years ago
A sky diver steps from a high-flying helicopter. if there were not air resistance, how fast would she be falling at the end of a
Rama09 [41]

If there is no air resistance and the body, in this case the sky diver simply falls from the helicopter then, the motion can be described as a free-falling body. The equation that would allow us to determine the speed of the body at any time, t is,

<span>                                    v(t)  = vo + gt</span>

<span>where v(t) is the unknown velocity, vo is the initial velocity which is equal to zero and g is the acceleration due to gravity which is equal to 9.8 m/s2.</span>

Substituting the known values,

<span>                                    v(t) = 0 + (9.8 m/s2)(12s)</span>

<span>                                                v(t) = 117.6 m/s</span>

<span>Hence, the speed of the sky diver at the end of 12 second is approximately 117.6 m/s.  </span>

8 0
2 years ago
A car is driving east at 120. km/h from Toronto to Ottawa. The distance between the two cities is 425.5 km, how long will it tak
Ket [755]

Answer:

The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds

Explanation:

The given parameters are;

Speed of the car = 120 km/h

Distance from Toronto to Ottawa = 425.5 km

The formula for speed is given as follows;

Speed = Distance/Time

Therefore, to find the time duration it takes from Toronto to Ottawa, we have;

Time duration = Distance from Toronto to Ottawa/(Speed of the car)

The time duration = 425.5/120 = 3.54583 hours = 212.75 min = 12765 seconds

The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.

4 0
2 years ago
A typical automobile under hard braking loses speed at a rate of about 7.2 m/s2; the typical reaction time to engage the brakes
Korvikt [17]

Answer:

4.3 m/s

Explanation:

a = rate at which the automobile loses speed = - 7.2 m/s²

v₀ = initial maximum speed of automobile

t' = reaction time for applying the brakes = 0.55 s

d = distance available for stopping the vehicle = 3.6 m

d' = distance traveled while applying the brakes = v₀ t' = (0.55) v₀

v = final speed after the vehicle comes to stop = 0 m/s

Using the equation

v² = v₀² + 2 a (d - d' )

0² =  v₀² + 2 (- 7.2) (3.6 -  (0.55) v₀)

v₀ = 4.3 m/s

7 0
2 years ago
Other questions:
  • Hydrogen-3 has a half-life of 12.35 years. What mass of hydrogen-3 will remain form a 100.0 MG initial sample after 5.0 years? A
    11·1 answer
  • Which equation is most likely used to determine the acceleration from a velocity vs:time graph?
    11·2 answers
  • Ben walks 500 meters from his house to the corner store. He then walks back toward his house, but continues 200 meters past his
    14·2 answers
  • You are driving to the grocery store at 20 m/s. You are 110m from an intersection when the traffic light turns red. Assume that
    14·1 answer
  • A uniform rectangular plate is hanging vertically downward from a hinge that passes along its left edge. By blowing air at 11.0
    9·1 answer
  • The Sun orbits the center of the Milky Way galaxy once each 2.60 × 108 years, with a roughly circular orbit averaging 3.00 × 104
    6·1 answer
  • On September 8, 2004, the genesis spacecraft crashed in Utah desert because it's parachute did not open. The 210-kg capsule hit
    14·1 answer
  • 1. Which of the following regarding a collision is/are true? a. If you triple your speed your force of impact will be three time
    11·2 answers
  • . A long 10-cm-diameter steam pipe whose external surface temperature is 110oC passes through some open area that is not protect
    8·2 answers
  • Calculate the true mass (in vacuum) of a piece of aluminum whose apparent mass is 4.5000 kgkg when weighed in air. The density o
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!